If three dies are thrown simultaneously probability of getting sum as 10?

• total possiblities =216
  possibility to get sum 10 is (1,6,3)=3!=6 ways
  (1,4,5)=3!=6ways
  (2,6,2)=3!/2!=3ways
  (2,5,3)=3!=6 ways
  (2,4,4)=3!/2!=3ways
  (3,3,4)=3!/2!=3ways
  total probability=(3+3+6+6+3+6)/216=27/216
• 10 years agoHelpfull: Yes(42) No(3)
• Total number of posibilties =6^3=216
  Getting sum 10=(1,4,5)-6ways
  (1,3,6)-6ways
  (2,4,4)-3ways
  (2,3,5)-6ways
  (2,2,6)-3ways
  (3,3,4)-3ways
  Total=21
  Probability =21/216
• 10 years agoHelpfull: Yes(5) No(13)
• Possible Sums with three dice are 3 ... 18
  
  3 -> 1+1+1 Possible Combinations: 1
  
  4 -> 1+2+1 Possible Combinations:3
  
  5 -> (1+3+1),(1,2,2) Possible Combinations:6
  
  6 -> (1,4,1), (1,3,2),(2,2,2) Possible Combinations:10
  
  7 -> (1,4,2), (1,3,3),(5,1,1),(3,2,2) Possible Combinations:15
  
  8 -> (1,4,3) , (1,2,5) ,(1,1,6),(4,2,2),(3,3,2) Possible Combinations:21
  
  9 -> (6,2,1) , (5,3,1) ,(5,2,2), (4,4,1) ,(4,3,2),(3,3,3) Possible Combinations:25
  
  10 -> (6,3,1) , (6,2,2) , (5,3,2), (5,4,1), (4,4,2),(4,3,3) Possible Combinations:27
  
  11 -> (6,4,1),(6,3,2),(5,5,1),(5,4,2) (5,3,3),(4,4,3) Possible Combinations:27
  
  12 -> (6,5,1),(6,4,2), (6,3,3),(5,5,2),(5,4,3),(4,4,4) Possible Combinations:25
  
  13 -> (6,6,1) ,(6,5,2),(6,4,3),(5,5,3),(5,4,4) Possible Combinations:21
  
  14 -> (6,4,4),(6,5,3),(5,5,4),(6,6,2) Possible Combinations::15
  
  15-> (6,6,3),(6,4,5),(5,5,5) Possible Combinations:10
  
  16-> (6,6,4),(6,5,5) Possible Combinations:6
  
  17-> (6,6,5) Possible Combinations3
  
  18-> 6,6,6 Possible Combinations:1
  
  Henceforth answer 27/216
• 9 years agoHelpfull: Yes(4) No(0)
• Probability of getting sum as 10 is 21/216.
• 10 years agoHelpfull: Yes(0) No(6)
• 3 dies=18 nos
  we have to make a grp of 3 nos which sum=10...
  we can permute 18 nos in different grp each consists 3=18P3
  now the possible combinations are:-
  1+6+3=10....6ways
  2+2+6=10...3 ways
  3+3+4....3 ways
  2+5+3.....6 ways
  4+4+2....3 ways
  1+4+5....6 ways
  =total 27 ways
  probability of sum 10=27/18P3=3/544
  
• 8 years agoHelpfull: Yes(0) No(0)