If two circles intersect with each other and from a square with side 1 cm with two centers and two intersecting points.Find intersecting area of circles ?

• side of square=radius of both circles=1cm
  intersecting area of circles =(pi*r^2)/4+(pi*r^2)/4 - area of square
  = (pi*r^2)/2-1
  = pi/2-1=1.57-1=.57cm^2
• 10 years agoHelpfull: Yes(36) No(2)
• as in the square we have 90deg angle in the edges so that the quadrant formed has an angle of 90deg so the area of the circle is divided into 4 parts... by adding the areas of the 2 quadrants and subtracting the area of the square we can get the area formed by the intersecting points..
  area of quadrant= pi/4*1^2
  for 2 quadrants we have pi/2
  area of square is 1^2
  area formed by intersecting points is (pi/2)-1=.57
• 10 years agoHelpfull: Yes(3) No(0)
• area will be 1 sq cm
• 10 years agoHelpfull: Yes(0) No(7)
• 1-(pi/4+pi/4)=(2-pi)/2
• 10 years agoHelpfull: Yes(0) No(5)
• side of square=radius of both circles=1cm
  intersecting area of circles =(pi*r^2)/4+(pi*r^2)/4 - area of square
  = (pi*r^2)-1
  = pi-1=2.14cm^2
• 10 years agoHelpfull: Yes(0) No(7)
• if you will draw the condition with two similar circles it will be clear that
  radius of both circles will be 1cm.
  as square is formed by centre to pt of intersection it makes 90 degree angle
  toata are of two circles = (pi.1^1)/4*2 = pi/2
  area of square 1*1 = 1
  subtract
  both and u ll get 0.57cm sqare
• 9 years agoHelpfull: Yes(0) No(0)