Elitmus
Exam
Numerical Ability
Area and Volume
Q. How many solution exists for (x+5)^1/2=x(x+5)^1/2
Option
1)1
2)2
3)3
4)4
Read Solution (Total 16)
-
- (x+5)^1/2=x*(x+5)^1/2
or (x+5)^1/2-x*(x+5)^1/2=0
or (x+5)^1/2*(1-x)=0
or (x+5)^1/2=0 ,1-x=0
or x=-5 ,x=1
only two solution
option(2) - 11 years agoHelpfull: Yes(48) No(1)
- (x+5)^2 = x*(x+5)^2
=> (x+5)= x^2 * (x+5)
=> x^2(x+5)-(x+5)=0
=> (x^2-1)(x+5)=0
=> x=+1,-1,-5
But x=-1 do not satisfy the original equation so only two values are there which are x=1 and x=-5
So answer is 2. - 11 years agoHelpfull: Yes(13) No(5)
- Only one solution can exist i.e X=1
so,option(1)
- 11 years agoHelpfull: Yes(4) No(6)
- (x+5)^1/2 = x*(x+5)^1/2
=> (x+5)= x^2 * (x+5)
=> x^2(x+5)-(x+5)=0
=> (x^2-1)(x+5)=0
=> x=+1,-1,-5
But x=-1 do not satisfy the original equation so only two values are there which are x=1 and x=-5
So answer is 2. - 11 years agoHelpfull: Yes(2) No(3)
- There are two solutions for this problem
equation satisfies for x=0 and 1
hence option(2) - 11 years agoHelpfull: Yes(1) No(6)
- the answer is 2 as only 1,-5 satisfies the given equation
- 11 years agoHelpfull: Yes(1) No(0)
- (x+5)^1/2=x*(x+5)^1/2
here two solution is possibel
1.(x+5)^1/2=x*(x+5)^1/2
or,(x+5)=x*(x+5)
or,x+5=x^2+5x
or,x^2+4x-5=0
or,(x-1)(x+5)=0
or,x=1 and x=-5 (x+5)^1/2
2.(x+5)^1/2=x*(x+5)^1/2
or,(x+5)^1/2/(x+5)^1/2=x
or,x=1
Which one is correct??????
- 11 years agoHelpfull: Yes(1) No(2)
- 2 solutions -5,5
- 11 years agoHelpfull: Yes(0) No(4)
- (x+5)^2 = x*(x+5)^2
(x+5)^2/(x+5)^2 = x
x=1 hence ans is 1 - 11 years agoHelpfull: Yes(0) No(0)
- ans is 3
equation satisfy for X=0,1,-5
- 11 years agoHelpfull: Yes(0) No(1)
- (x+5)^1/2(1-x)=0
then from this
1-x=0
x=0
and (x+5)1/2=0 is a positive number which can't be zero hence only one solution - 11 years agoHelpfull: Yes(0) No(0)
- why x=-1 dusnt satisfy d equation??
- 11 years agoHelpfull: Yes(0) No(0)
- (x+5)^1/2(1-x)=0
then from this
1-x=0 then
x=1
and (x+5)1/2=0 is a positive number which can't be zero hence only one solution
- 11 years agoHelpfull: Yes(0) No(0)
- given that
(x+5)^1/2=x(x+5)^1/2
therefore
(x+5)^1/2*(1-x)=0
(x+5)^1/2=0 and 1-x=0
hence; x=-5 and x=1.
now option 2 is correct. - 11 years agoHelpfull: Yes(0) No(0)
- 3 solutions
(x+5)^1/2 = x*(x+5)^1/2
Squaring both sides
x+5 = ( x^2 ) * (x+5)
x+5 = x^3 + 5x^2
=> x^3 + 5x^2 - x -5 = 0
=> x^2(x+5) -1 (x+5)=0
=> (x^2 - 1) ( x + 5 )=0
One solution -5
Now x^2-1=0
(x-1)(x+1)=0
x=-1,1
So total 3 solutions 1,-1,-5 - 11 years agoHelpfull: Yes(0) No(2)
- (x+5)^1/2=x(x+5)^1/2
oor (x+5)^1/2-x*(x+5)^1/2=0
or (x+5)^1/2*(1-x)=0
- 11 years agoHelpfull: Yes(0) No(0)
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