Q. Two trains start at the same time one from Basar other from Hyderabad and running towards each other one at 160 kmph and other at 20kmph. When they meet each other which one will be nearer to Hyderabad

• suppose if you consider the distance between hyderbad and basar 360 then they will meet after x min so
  360=(160*x)+(20*x)
  x=2hours
  then train1 travelled 320 km from basar towards Hyderabad i.e it is 40 km away from Hyderabad.then train2 travelled 40km away from Hyderabad then it is 40km away from Hyderabad so both are at same distance from Hyderabad.
• 11 years agoHelpfull: Yes(21) No(4)
• when the two trains will meet at a certain point of distance then the front end of both the trains will coincide hence will be considered as a common point and the distance from that common point to any point will be equal. whetther the distance is measured from hyderabad to the point of meeting or the distance is measured from basar to the point of meeting.
• 10 years agoHelpfull: Yes(7) No(0)
• Both are at the same distance.
• 11 years agoHelpfull: Yes(5) No(1)
• once they meet than Hyderabad will be at same distance from each other.
• 11 years agoHelpfull: Yes(3) No(3)
• WHy everyone is saying at same distance same distance
  if u know the logic just explain it here
  dont make others fool
• 10 years agoHelpfull: Yes(2) No(1)
• plz explain clearly...
• 11 years agoHelpfull: Yes(1) No(2)
• both at same location so equal distance from hyderabad
• 11 years agoHelpfull: Yes(1) No(1)
• It depending on distance between them.
  if dist180 then other
• 10 years agoHelpfull: Yes(1) No(0)
• B
  A
  H......................B
  So when the met, they were at same distance from hydrabad. no calculation is needed ;)
• 10 years agoHelpfull: Yes(1) No(4)
• data insufficient
• 10 years agoHelpfull: Yes(1) No(0)
• Both are at same distance.
  
• 10 years agoHelpfull: Yes(0) No(0)
• the train having speed 20kmph will be near to the Hyderabad.....because meeting takes place at (L/9)from Hyderabad.....
• 10 years agoHelpfull: Yes(0) No(0)
• No need to solve the quesition as at the meeting time both the train will have equal distances from both the stations.
• 10 years agoHelpfull: Yes(0) No(0)
• Both will be at same distance from hyderabad.
• 9 years agoHelpfull: Yes(0) No(0)
• when they meet both the trains will be at the same distance from Hyderabad
• 9 years agoHelpfull: Yes(0) No(0)
• let the bridge be L miles long. Let Anoop run v miles per hour.
  
  Hence by the time Anoop runs to EITHER END of the railroad bridge, the train just comes to the SAME end of the bridge.
  
  1) Anoop runs L - 5L/6 = L/6 distance, to the nearer end of the bridge.
  The train has to run through the distance x.
  
  frac{L/6}{v} = frac{x}{35} => v = frac{35 L}{6 x}, - equation 1
  
  2) Anoop runs 5L/6 to the farther end of the bridge.
  
  frac{L+x}{35} = frac{5L/6}{v}, => v = frac{35*5 L}{6 (L+x)}, - equation 2
  
  divide equation 2 by equation 1 =>
  1 = frac{5 x}{L+x}, => L + x = 5 x, L=4 x, - equation3
  
  
  substitute in equation 1,
  v = frac{35 * 4 x}{6 * x} = frac{140}{6} = 23.66 mph\
  
  Anoop can run at 23.66 mph
  
• 9 years agoHelpfull: Yes(0) No(2)
• Data insufficient .......distance must required
  
• 9 years agoHelpfull: Yes(0) No(0)