Q. There are 2 pesons each having same amount of marbles in the beginning. after that 1 person gain 20 more from second person n he eventually lose two third of it during the play n the second person now have 4 times marble of what 1st person is having now. find out how much marble did each had in the beginning

• Ans :100
  Let two persons initially have x marbles,then after 1st play 1 person gain 20 more from second person
  therefore after 1st play 1st person has x+20 and second person has x-20
  after 2nd play he eventually lose two third of it during the play n the second person now have 4 times marble of what 1st person is having now
  after losing 2/3(x+20) 1st person now will have 1/3(x+20)
  Second person will have (x-20)+2/3(x+20)
  Given second person now have 4 times marble of what 1st person is having now
  therefore (x-20)+2/3(x+20)=4*1/3(x+20)
  Therefore x=100
  Thus initially each have 100 marbles in the beginning.
  
• 10 years agoHelpfull: Yes(47) No(3)
• ans is..each having 50-50 marbles
  1st=> 50 50
  2nd=> 60 40
  32d=> 20 80...condition satisfy..
• 10 years agoHelpfull: Yes(5) No(7)
• 1st person 2nd person
  
  m m
  m+20 m-20 m+20)-2/3(m+20) (m-20)+2/3(m+20)
  
  
  (m-20)+2/3(m+20)=4((m+20)-2/3(m+20))
  
  m=100
  
• 10 years agoHelpfull: Yes(2) No(2)
• qus said that in !st round A have 20 more then B...but in ur ans A have 40 more than B
• 10 years agoHelpfull: Yes(1) No(1)
• initially x
  after 1st round 1st person has x+10 and scnd one has x-10
  after second play 1st one looses 2/3rd of his marbels . so he has now 1/3(x+10) and second one has (x-10)+2/3(x-10)
  according to question
  (x-10)+2/3(x-10)=4*1/3(x+10)
  solving this we get x=50
  
  
• 9 years agoHelpfull: Yes(0) No(0)