Q If a dice has 1 6 and 3 4 and 2 5 opposite each other how many such dies

Suppose if you take any of the first pair. Let (1,6) this pair can be placed in 6 ways .after placing pair we have only 2 pairs. then by taking 2nd pair let(3,4), it can be placed in 2 pairs of 4 places. after this we have only 1 pair.in this remaining pair can be placed in 2 ways.so totally
6+4+2= 12 ways.
10 years agoHelpfull: Yes(6) No(0)
its 3! * 2 = 12
10 years agoHelpfull: Yes(5) No(0)
hey vanithareddy cud u pls xplain me dis:

(1,6),(3,4),(2,5) are 3 possible opposite side sets required
These three can be arranged in above blank cube in 3*3 = 9 ways
since each set has 3 option and other two will also have 3 each... therefore it shud b 3*3??? if NO den y hav u taken 2*3?? i didnt gt d concept of 2?? pls xpalin
and further in my logic, it shud be
Each of these pairs can be arranged in 2 ways (1,6) or (6,1).

Therefore Total number of dice possible = 9*2 = 18.. pls comment if i am thinking in a wrong way.
10 years agoHelpfull: Yes(4) No(12)
2*2*2=8

8 dies can be made
10 years agoHelpfull: Yes(2) No(7)
Plz. explain in detail....
10 years agoHelpfull: Yes(0) No(1)
6 dies can be made
1,6 2,4 3,4 4,3 5,2 6,1
addition is 7
10 years agoHelpfull: Yes(0) No(7)
3 .1 6=1, 25 =2,34=3.
10 years agoHelpfull: Yes(0) No(0)
Total 10 combinations
9 years agoHelpfull: Yes(0) No(0)

Q. If a dice has 1,6 and 3,4 and 2,5 opposite each other how many such dies can be made.