elitmus
Exam
Numerical Ability
Number System
Q. How many 1's present in the binary form of number 519*1024+11*64+3
Read Solution (Total 21)
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- Easiest way to do this type of questions:
519*1024+11*64+3 = (2^9+2^2+2^1+2^0)*(2^10)+(2^3+2^1+2^0)*(2^5)+(2^1+2^0) = 2^19+2^12+2^11+2^10+2^8+2^6+2^5+2^1+2^0
number of 2^something = number of 1's = 9 (answer) - 11 years agoHelpfull: Yes(14) No(3)
- 9 1's are present
- 11 years agoHelpfull: Yes(7) No(4)
- ans=9 1's
519*1024+11*64+3
lets start with multiplication,
519*1024 =1000000111*10000000000 (binary multiplication)= 10000001110000000000
1.e 1000000111 followed by 10 zeros
11*64=1011 * 1000000 = 1011000000 (total 10 digit)
at last
3=11
(it is clear here no need of further addition)
total 1's = 4+3+2 =9
- 11 years agoHelpfull: Yes(6) No(0)
- 1000000111+10000000000+1011+1000000+11= eleven(11) ones(1) are present... so option is 11
(Hint: divide the numbers with 2) - 11 years agoHelpfull: Yes(5) No(7)
- 10 1's are there
- 11 years agoHelpfull: Yes(3) No(2)
- 9 times "1"
- 11 years agoHelpfull: Yes(2) No(1)
- options were 1)9 2)10 3)12 4)none of these.
there was no 11 there.
and we have to find the number of 1's in the number we get by adding all these. - 11 years agoHelpfull: Yes(2) No(1)
- there are 9 ones
- 11 years agoHelpfull: Yes(2) No(1)
- 11 one's present.1st see in 512 ,one 1 is their,and(512+7)in 7 three 1 are their.so in 519 ,4 ones are their and in 1024 one 1 is present.and operation of 519 and 1024 gives 5 ones...like this u hav to do..
- 11 years agoHelpfull: Yes(1) No(4)
- 519*1024+11*64+3 = 532136 ( by solving )
then convert into binary by dividing 2... u will get binary number which consists 9 '1'.... so ans is 9.... sure..... just do it....
- 11 years agoHelpfull: Yes(1) No(0)
- 519*1024+11*64+3 can be written as=
(2^9+2^2+2^1+2^0)2^10+(2^3+2^1+2^0)2^6+2^1+2^0
=2^19+2^12+2^11+2^10+2^9+2^7+2^6+2^2+2^0
= 9 times 1
hence there are 9 1's - 11 years agoHelpfull: Yes(1) No(0)
- 10 ones will the answer just find binary of 532163..
- 10 years agoHelpfull: Yes(1) No(2)
- options were 9,10,11 none of the above ..
none !! - 11 years agoHelpfull: Yes(0) No(0)
- option are 8,9,10,none
- 11 years agoHelpfull: Yes(0) No(0)
- nagireddy ,paras ..how did u get 9? ...the mul resultsin 532163 takin it t binay u"l get more 1"s
- 11 years agoHelpfull: Yes(0) No(0)
- @paras are u sure about the options were 8,9,10 and none
- 11 years agoHelpfull: Yes(0) No(0)
- answer is 9 yr , no more discussion!!
warna 2.5 kilo ka hath mu p padega!! :P - 11 years agoHelpfull: Yes(0) No(1)
- value is 82163.so bianary value is 1011101100111.SO,9 1's are present.
- 11 years agoHelpfull: Yes(0) No(0)
- 11 1's present
- 9 years agoHelpfull: Yes(0) No(0)
- 519*1024+11*64+3=605891
605891 binary is 10010011111011000011
ie 11 1's present - 9 years agoHelpfull: Yes(0) No(0)
- CORRECT ANSWER =11
- 8 years agoHelpfull: Yes(0) No(0)
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