Q. How many such numbers are possible such that 2*3*6=36

• we have to find all the 3 number combinations such tht they form 36.so we cn do it like:
  1*4*9=36 number of ways it cn be done is 6.
  1*6*6=36 number of ways it cn be done is 3.(166,616,661)
  2*3*6=36 number of ways or arrangement of 2,3,6 yields 6 ways.
  2*9*2=36 number of ways it cn be done is 3.
  3*4*3=36 number of ways it cn be done is 3.
  so adding all of the above we have 6+3+6+3+3=21 ways
• 10 years agoHelpfull: Yes(13) No(1)
• how to proceed
  1st no* 2nd no*(1st*2nd)=(1st*2nd)^2
  or
  1st no* 2nd no*(1st*2nd)=2nd(1st*2nd)
• 11 years agoHelpfull: Yes(3) No(2)
• Any body who has solved this please explain the question!!!!!!!
  
• 11 years agoHelpfull: Yes(2) No(0)
• all the options are greater than 60
• 11 years agoHelpfull: Yes(0) No(0)
• 3!=6 ways.
• 11 years agoHelpfull: Yes(0) No(4)
• 1)series is 1,9,81,729
  
  2)let n =2, so ( 1(9^2-1)/9-1 )/6 = 80/(8*6) = 80 / 48 .
  so divisible by 2 is not an answer.
  
  3)let n=3, so ( 1(9^3-1)/9-1 )/6 = 729-1/(8*6) = 728/48 =2*2*2*7*13/2*2*2*2*3
  so divisible by 3 is not an answer ,
  somebody try remaining 2 options .
• 11 years agoHelpfull: Yes(0) No(2)
• ans-1
  because it follows the pattern as 1st-no*2nd-no=3rd no
  and rhs part will be equal to the 2nd-no 3rdno,i.e it will be in the
  form a*b*c=bc
  so only 2*4*8=48
• 10 years agoHelpfull: Yes(0) No(2)