Q. How many binary 1 in this 569*1024+525*64+32

• this whole can be written as (2^9+2^5+2^4+2^3+2^0)2^10 +(2^9+2^3+2^2+2^0)2^6 +2^5
  
  = 2^19+2^16+2^14+2^13+2^10+2^9+2^8+2^6+2^5
  
  =101101111000110000
  so there are 9 1's.
• 11 years agoHelpfull: Yes(25) No(1)
• ans-9 firstly u can solve then u change in to binary form its come 9 1's..
• 11 years agoHelpfull: Yes(2) No(3)
• no=618288
  binary =101101111000110000.
  9 1's.
• 11 years agoHelpfull: Yes(2) No(2)
• 10010110011101100000 ans is 9
  
• 9 years agoHelpfull: Yes(2) No(0)
• 616228 = 10010110011100100100
  
  so, 9
• 11 years agoHelpfull: Yes(1) No(0)
• 10 is the answer
  569 has 5 ones in the binary
  1024 has 1 ones
  525 has 4 ones
  64 has 1 ones
  32 has 1 ones
  so total 10
• 7 years agoHelpfull: Yes(1) No(0)
• Firstly calculate the final result of above expresion,the result came is 618288
  then,convert 618288 into binary ,then count the number of 1's appear in final result..thus the number of 1's are 9
• 11 years agoHelpfull: Yes(0) No(0)
• 512 , 1024, 64 = 1(No. of 1) {Any no. such as x = 2^n, will have only one 1 in binary}
  255 = 8 (No. of 1)
  3 = 2
  
  => 1*1+8*1+2
  => 11
• 9 years agoHelpfull: Yes(0) No(0)
• no=618288
  binary=10010110111100110000
  so there are 10 1's
  i have solve this qustion through calculator and ans is 10 1's
  you can convert this no into binary by using this link
  http://www.binaryhexconverter.com/decimal-to-binary-converter
• 9 years agoHelpfull: Yes(0) No(0)