Q. A boy travels in a scooter after covering 2/3rd of the distance the wheel got punctured he covered the remaining distance by walk. Walking time is twice that of the time the boy?s riding time. How many times the riding speed as that of the walking speed?

• let the total distance =x
  distance travelled by scooter=2/3 * x
  time taken t = (2/3 * x)/ speed of the scooter
  distance travelled by walk = x/3
  time taken 2*t (given) = (x/3)/speed of the person
  speed of the scooter/ speed of the person = (2*x/3*t)/(x/6*t) = 4:1
• 10 years agoHelpfull: Yes(32) No(3)
• speed(scooter)=(2/3)/t and speed(walk)=(1/3)/2t
  solving both we will get 4:1
  so ans is 4 times
• 10 years agoHelpfull: Yes(11) No(0)
• total distance=x
  2x/3/y
  riding speed=ykm/hr
  walking speex=zkm/hr
  x/3z
  x/3z=4x/3y
  1/z=4/y
  y=4z
  
• 10 years agoHelpfull: Yes(4) No(0)
• assume speed by scooter s1 , speed by walk s2
  distance x
  time T
  
  s1=2x/3T
  s2=x/6T
  
  now s1/s2=4
  so s1=4*s2
  4 times the riding speed as that of walking speed..
• 10 years agoHelpfull: Yes(3) No(0)
• ratio is 4/1
• 9 years agoHelpfull: Yes(1) No(0)
• (x/20+2+(x/4)+2+(x/8)+2+(x/16)+2=x;where x is the total no. of diamonds;
  =>((8x+4x+2x+x)/16)=x-8
  =>15x/16=x-8
  =>16x-128=15x
  =>x=128
  =>total no. of diamonds=128
• 10 years agoHelpfull: Yes(0) No(6)
• 4 times riding speed than walking
• 10 years agoHelpfull: Yes(0) No(0)
• 4times
  s1/s2=(d1*d2)(t2/t1)
  d1=2/3*x
  d2=1/3*x
  t1=t
  t2=2t
  subsitute u get 4:1
• 10 years agoHelpfull: Yes(0) No(0)