Q. In a software company 2/6 of people know C++,1/2 of them know java,1/5 of them know neither,find the total possibility to know C++?

• possibility of knowing c++= 2/6
  possibility of knowing java=1/2
  
  there are 4 possibilities,
  a person knows java but not c++=1/2*(1-(2/6))=1/3
  a person knows c++ but not java= 2/6*(1-(1/2))=1/6
  possibility of knowing neither =1/5
  therefore, probability of knowing any one language only= 1/6+1/3=1/2
  therefore possibility of knowing both= total probability- probability of knowing neither- probability of knowing anyone language only
  total probability is always 1
  so, required probability= 1 -(1/5) -(1/2) =3/10
• 10 years agoHelpfull: Yes(58) No(9)
• C++ Known people = 2/6,
  Java Known people =1/2,
  Neither C++ Nor Java = 1/5,
  So,both known = 4/5,
  Only C++ = 4/5(Both Known) - 1/2(java Known people)
  = (8-5)/10
  = 3/10.
• 8 years agoHelpfull: Yes(25) No(0)
• Consider the total no. of people to be 30.(LCM of 6,2 and 5).
  Now, people knowing C++ is 2/6*30=10. Therefor, possibility of people knowing C++ may be 10/30=1/3
  Ans)1/3
• 10 years agoHelpfull: Yes(24) No(8)
• 1/2 + 1/5 + 2/6= 31/30
  
  ans.=2/6 / 31/30= 10/31
• 10 years agoHelpfull: Yes(9) No(10)
• Ans-2/15
  2/6 * 1/2 *(1-(1/5))=2/15.
• 10 years agoHelpfull: Yes(8) No(17)
• possibility of knowing c++=2/6
  possibility of knowing java=1/2
  
  remaining=1-(2/6+1/2)=1/6
  neither java and neither c++ =1/5
  therefore....
  probability of knowing both java and c++ =nether probability - remaining
  =1/5-1/6=1/30
  
  probability of knowing only c++=2/6-1/30=3/10 (ans)
  
  
• 9 years agoHelpfull: Yes(8) No(0)
• sum one give exact solution plzzzzzzzzzzzzzzz
  
• 10 years agoHelpfull: Yes(6) No(5)
• let total people=x
  people knowing C++=2/6x
  people knowing java=1/2x
  neither=1/5x
  both c++&java knowing people=2/6x+1/2x-1/5x=19/30x
  total possibility to know C++=2/6*19/30
  19/90
  
• 9 years agoHelpfull: Yes(5) No(3)
• 
  so, required probability= 1 -(1/5) -(1/2) =3/10
  Read more at http://www.m4maths.com/31483-In-a-software-company-2-6-of-people-know-C-1-2-of-them-know-java-1-5-of-them.html#yzyjKBtxktQscPqm.99
• 9 years agoHelpfull: Yes(2) No(4)
• C++ Known people = 2/6,
  Java Known people =1/2,
  Neither C++ Nor Java = 1/5,
  So,both known = 1 - 1/5 = 4/5,(because total probability is 1)
  Only C++ = 4/5(Both Known) - 1/2(java Known people)
  = (8-5)/10
  = 3/10.
• 7 years agoHelpfull: Yes(1) No(0)