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Numerical Ability
Age Problem
3 years ago Jacob's age was twice John's age. 3 years hence Jacob's age will be 4/3 times the age of John's. Find Jacob's present age in binary numbers.
Read Solution (Total 2)
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- let present age of jacob is X year;
and present age of john is Y year;
now 1st statement says: (X-3)=2(Y-3);
and 2nd statement says: (X+3)=4/3(Y+3);
hence solving these equations we get: X=9 and Y=6;
and hence jacobs age will be in binary: 1001. - 13 years agoHelpfull: Yes(12) No(1)
- let jacobs age be x..n johns age b y(present ages)
3 yrs earlier..(x-3)=2(y-3)
3 yrs later..(x+3)=4/3(y+3)
solving u vl get..x=12&y=6
convert x into binary num..u vl get d answer - 13 years agoHelpfull: Yes(3) No(3)
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