Two liquids A and B are in ratio 5:1 in container 1 and in container 2, they are in ratio 1:3. In What ratio should the contents be mixed of A and B in the ratio of 1:1

• let the total liquid in container = x
  quantity of A in container 1 = 5x/6
  quantity of B in container 1 = x/6
  quantity of A in container 2 = x/4
  quantity of B in container 2 = 3x/4
  new ratio of A and B = 1:1
  let quantity container 1 mix = n
  let quantity container 2 mix = m
  =>now Quantity of A = 5xn/6 + xm/4 = x(5n/6 + m/4)
  =>now Quantity of B = xn/6 + 3xm/4 = x(n/6 + 3m/4)
  As new quantity of A and B are equal
  => 5n/6 + m/4 = n/6 +3m/4
  => 4n/6 = 2m/4
  => n/m = 3/4
  
• 13 years agoHelpfull: Yes(34) No(7)
• ANSWER : 3:2
  
  SOLUTION :
  
  Let the ratio of mixing container 1 : container 2 is x:y
  
  container 1 contribute
  A = 5x/6
  B = x/6
  Container 2 contribute
  A = y/4
  B = 3y/4
  
  Equating A = B
  ie
  5x/6 + y/4 = x/6 + 3y/4
  
  We get x/y = 3/2
• 13 years agoHelpfull: Yes(16) No(20)
• container 1 has 5/6 of a
  and 2 container has 1/4 of a
  and final mixture has 1/2 of a
  so by mixture we can get a ratio =3:4
  ans
• 13 years agoHelpfull: Yes(5) No(7)
• let liquid in container 1 be 5litre and 1 litre
  and liquid in container 2 be 2litre and 6 litre.
  on adding we get 7 litre of both a and b.
  hence they should be added in ratio 1:2.
  
• 13 years agoHelpfull: Yes(4) No(13)
• let take two containers c1 and c2 n use basic allegation method
  in c1 qty. of A = 5/6 = 20/24
  in c2 qty. of A = 1/4 = 6/24
  in mixture qty. of A = 1/2 = 12/24
  c1 c2
  
  20/24 6/24
  
  12/24
  
  6/24 8/24
  
  3 4
  
  =3:4
  
• 9 years agoHelpfull: Yes(4) No(0)
• Take 1 portion from container 1 and N portions from container 2.
  
  Then we collect in total 5/6A + 1/6B + N(3/4B + 1/4A) i.e.:
  
  (5/6 + N/4)A = (3N/4 + 1/6)B
  
  in order for this to be a 1 : 1 mixture, the coefficients of A and B must be equal, i.e.
  
  (5/6 + N/4) = (3N/4 + 1/6) solving which gives N = 4/3 i.e 4 portions of B to 3 of A = solution D.
• 11 years agoHelpfull: Yes(2) No(2)
• for first solution a:b=5:1 so a is present in 5/6 of the solution ......
  for second solu a:b=3:4 so a present in 3/4 of the solution ....... and in the solution desired it is in the ratio of 1:1 so a is 1/2 of solution
  
  5/6 3/4
  1/2
  (3/4-1/2)=1/4 (5/6-1/2)=1/3
  
  
  
  (1/4)/(1/3)=3:4 (ans)
• 9 years agoHelpfull: Yes(2) No(0)