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Consider a school which consists of boys,girls and teachers. Girls strength is twice as boys. During prayer this school follows some procedure which is bowing each other. Each girl bow every other girls,boys and teacher. And each boy bow every other boys,girls and teachers.There are totally 900 bows find how many boys and girls are there in the school ?

Read Solution (Total 7)

Girls strength is twice as boys

SO let us consider girls=20 boys=10 teacher=1

Given that Each girl bow every other girls,boys and teacher.
so one girl will bow remaining 19 girls + 10 boys + 1 teacher = 30 bow
1 girl = 30 bow
so for 20 girl = 20 * 30 = 600 bows.

Again given that each boy bow every other boys,girls and teachers.
so 1 boy will bow remaining 9 boys + 20 girls + 1 teacher = 30 bow
1 boy = 30 bows
for 10 boys = 10 * 30 = 300 bows

so totally 300(boys bows) + 600 (girls bows) = 900 bows.
10 years agoHelpfull: Yes(10) No(1)

here tot 900 bows and girls : boys ratio in the school is 2:1
so the ans will be G=600,B=300
10 years agoHelpfull: Yes(3) No(4)
let number of boys= n
NO of girls =2n
total no of bow by each girl and each boy to each other =(2n+n)c2 =(3n)c2
total no of bow given to teacher by girls =2n
total no of bows given to teacher by boys= n
total no bows =(3n)c2 + 2n + n
900 =3n*(3n-1)+2n+n
900 =9(n^2)-3n+3n
900 = 9(n^2)
n=10
so boys =10
girls =20
10 years agoHelpfull: Yes(2) No(0)
450
total 900 bows
so girls=2(boys)
900=2(450)
10 years agoHelpfull: Yes(1) No(0)
It's like handshake problem.
answer is 15 boys,30 girls and 4 teachers
10 years agoHelpfull: Yes(0) No(2)
in the previous one in place of (3n)c2 it should be (3n)p2
I just got confused the formula
10 years agoHelpfull: Yes(0) No(0)
bow bow bow :p
10 years agoHelpfull: Yes(0) No(2)

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