Find the number of solutions for 3x+4y=60, if x and y are positive integers.

• 3x+4y=60
  =>x=(60-4y)/3
  as x and y are positive integers, put y=1,2,3,... & find x
  y=3,x=16
  y=6,x=12
  y=9,x=8
  y=12,x=4
  (x,y)=(4,12),(8,9),(12,6),(16,3)
  only 4 solution
  
• 10 years agoHelpfull: Yes(21) No(1)
• Totally 6 solutions....
  Y=15 & X=0
  Y=12 & X=4
  Y=9 & X=8
  Y=6 & X=12
  Y=3 & X=16
  Y=0 & X=20
• 10 years agoHelpfull: Yes(7) No(7)
• 8 solutions. according to manoj 4 and then interchange the values of x and y.
• 10 years agoHelpfull: Yes(6) No(18)
• the answers can x=12 and y=4,x=10 and y=7.5,x=8 and y=9
• 10 years agoHelpfull: Yes(1) No(0)
• (x,y)=(4,12) ,(8,9) ,(12,6) ,(16,3) ----------only four solutions
• 10 years agoHelpfull: Yes(0) No(1)
• 3x=60-4y
  
  keep substituting values for y such that (60-4y) will be divisible by 3. This can be done by substituting y as multiples of 3 (0,3,6,9,12,etc...). but since its mentioned x,y are positive integers,
  60-4y>=0
  therefore
  y>=15
  
  so values of y = 0, 3, 6, 9, 12 and 15
  corresponding values of x = 20,16, 12, 8, 4, 0
• 10 years agoHelpfull: Yes(0) No(0)
• Infinetly many solutions
• 9 years agoHelpfull: Yes(0) No(0)
• ANS :
  3x must generate values that would make RHS divisible by 4 . Hence x=0,4,8,12,16,20
  Number of solutions = 6
  
• 9 years agoHelpfull: Yes(0) No(0)