How many integers between 50 and 100 can be evenly divided by neither 3 nor 5?

• divisible by 3 between 50 and 100 = 17 (51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99)
  
  divisible by 5 between 50 and 100 = 9 (55,60,65,70,75,80,85,90,95)
  
  Common divisible for 5 and 3 = 3 (60, 75, 90)
  
  Total divisible by 5 and 3 between 50 and 100 = 17+9-3 => 23
  
  There are 49 numbers between 50 to 100 i.e 51 to 99
  
  so the integers that are not divisible by 3 and 5 => 49 - 23 => 26
  
  
• 10 years agoHelpfull: Yes(28) No(0)
• divisible by 3 between 50 and 100 = 16 (51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,99)
  
  divisible by 5 between 50 and 100 = 11 (50,55,60,65,70,75,80,85,90,95,100)
  
  Common divisible for 5 and 3 = 3 (60, 75, 90)
  
  So, total divisible by 5 and 3 between 50 and 100 = 16+11-3 => 24
  
  Therefore the integers that are not divisible by 3 and 5 = 51 - 24 => 27
• 10 years agoHelpfull: Yes(3) No(13)
• 24
• 10 years agoHelpfull: Yes(2) No(1)
• 26
  count of numbers divided by 3 : 17
  count of numbers divided by 5 : 11
  count of numbers divided by both 3 and 5 : 3
  so totally 17 + 11 - 3 = 25
  51 - 25 = 26
• 10 years agoHelpfull: Yes(2) No(1)
• total 18 integers
  51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
• 10 years agoHelpfull: Yes(1) No(4)
• 
  total divisible by 5 and 3 between 50 and 100 = 16+11-3 => 24
  not divisible = 49 - 24= 25
• 10 years agoHelpfull: Yes(1) No(0)
• divisible by 3 between 50 and 100 = 17 (51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99)
  
  divisible by 5 between 50 and 100 = 9 (55,60,65,70,75,80,85,90,95)
  
  Common divisible for 5 and 3 = 3 (60, 75, 90)
  
  Total divisible by 5 and 3 between 50 and 100 = 17+9-3 => 23
  
  There are 49 numbers between 50 to 100 i.e 51 to 99
  
  so the integers that are not divisible by 3 and 5 => 49 - 23 => 26
  
• 9 years agoHelpfull: Yes(1) No(0)
• divide/3 numbers are={51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99}=count(17)
  divide/5 numbers are={55,60,65,70,75,80,85,90,95,}=count(9)
  common numbers are={60,75,90}=count(3)
  left out the common numbers= total((17+9)-3)
  =26-3
  total numbers are starts from 51 to 99 is 49
  =49-23
  answer=26
• 9 years agoHelpfull: Yes(1) No(0)
• 24
  total-no.of divisible
  (51-27)=24 (divisible by 3=17,divisible by 5=10)
• 10 years agoHelpfull: Yes(0) No(1)
• divisible by 3 between 50 and 100 = 16 (51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,99)
  
  divisible by 5 between 50 and 100 = 9 (55,60,65,70,75,80,85,90,95)
  
  Common divisible for 5 and 3 = 3 (60, 75, 90)
  
  Total divisible by 5 and 3 between 50 and 100 = 16+9-3 => 22
  
  There are 49 numbers between 50 to 100 i.e 51 to 99
  
  so the integers that are not divisible by 3 and 5 => 49 - 22 => 27
• 10 years agoHelpfull: Yes(0) No(3)
• answer = 15
  
  numbers between 50 and 100 = 49
  
  numbers not divisible by 3 or 5 = 49 - 23 = 26
  
  since evenly divided, number of prime numbers between 50 and 100 = 11
  
  so, 26 - 11 = 15
• 9 years agoHelpfull: Yes(0) No(0)
• answer = 15
  
  numbers between 50 and 100 = 49
  
  numbers not divisible by 3 or 5 = 49 - 23 = 26
  
  since evenly divided, number of prime numbers between 50 and 100 = 11
  
  so, 26 - 11 = 15
• 9 years agoHelpfull: Yes(0) No(1)
• 26 intergers
  52,53,56,58,59
  61,62,64,67,68,
  71,73,74,76,77,79,
  82,83,86,88,89,
  91,92,94,97,98
• 9 years agoHelpfull: Yes(0) No(0)
• divisible by 3 between 50 and 100 = 17 (51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99)
  
  divisible by 5 between 50 and 100 = 9 (55,60,65,70,75,80,85,90,95)
  
  Common divisible for 5 and 3 = 3 (60, 75, 90)
  
  Total divisible by 5 and 3 between 50 and 100 = 17+9-3 => 23
  
  There are 49 numbers between 50 to 100 i.e 51 to 99
  
  so the integers that are not divisible by 3 and 5 => 49 - 23 => 26
• 9 years agoHelpfull: Yes(0) No(0)
• divisible by 3 and 5 are 51,54,55,57,60,63,65,66,69,70,72,75,78,80,81,84,85,87,90,93,95,96,99...totally 23 numbers are divisible by 3 and 5....so,48(between 50 and 100 ,so 50&100 neglected) - 23 ==== 25 numbers can be evenly divided by neither 3 nor 5
• 8 years agoHelpfull: Yes(0) No(0)
• 23 integers will not be neither divided by 3 or 5.
  
• 8 years agoHelpfull: Yes(0) No(0)
• ANS : 26
  17 numbers divisible by 3 from 50 to 100
  11 numbers divisible by 5 from 50 to 100
  So 26 numbers in total
  51-26=25 integers
• 8 years agoHelpfull: Yes(0) No(0)