Q Find the 8th term 3 11 31 69 131

the right ans is 521
10 years agoHelpfull: Yes(21) No(0)
1^3+2=3
2^3+3=11
3^3+4=31
4^3+5=69
5^3+6=131
therefore 6^3+7=223
10 years agoHelpfull: Yes(6) No(6)
T(n)= n^3 + (n+1)
So,
T(1) = 1^3 + (1+1) = 3
T(2) = 2^3 + (2+1) = 11
T(3) = 3^3 + (3+1) = 31
T(4) = 4^3 + (4+1) = 69
T(5) = 5^3 + (5+1) = 131
T(6) = 6^3 + (6+1) = 223
T(7) = 7^3 + (7+1) = 351
T(8) = 8^3 + (8+1) = 521

Hence , The required answer is 521
10 years agoHelpfull: Yes(4) No(1)
3 11 31 69 131 223 351 521
8 20 38 62 92 128 170
12 18 24 30 36 42

so 521 is d answer....
10 years agoHelpfull: Yes(3) No(1)
3 11 31 69 131
8 20 38 62
12 18 24
6 6
that means 24=6=30
30=62=92
92+131=223
ans is 223 ???
10 years agoHelpfull: Yes(2) No(2)
sorry this is the 6 th term....521 is the ans.
10 years agoHelpfull: Yes(2) No(0)
the difference between successive terms is 8,20,38,62 whose difference in turn is 12,18,24 in ap. and the next term of this ap is 30. so the successive difference between terms shud be 62+30=92. therefore nxt term is 131+92=223 ans.
10 years agoHelpfull: Yes(1) No(1)
1^3 + 2=3
2^3 + 3=11
3^3 +4=31
4^3+5=59
5^3+6=131
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8^3+9=521
10 years agoHelpfull: Yes(1) No(0)
521 as series follow a^3+n
6 years agoHelpfull: Yes(1) No(0)
1^3+2=3,
2^3+3=11,
3^3+4=31
....
similarly 8th number
8^3+9=521
9 years agoHelpfull: Yes(0) No(0)

Q. Find the 8th term ...
3,11,31,69,131