Q. Find four digit number fromed given digits 1,2,3,4,5,5,6,6

• Updated:
  
  1.nos containing only 1,2,3,4,5 and 6:6C4x4!=360
  2.nos containing two 5's(Ex:5512):(5C2x4!)/2!=120
  3.nos containing two 6's(Ex:6612):(5C2x4!)/2!=120
  4.nos containing two 5's and 6's(Ex:5566):(4!)/2!x2!=6
  Total nos:360+240+6=606
  
  
  
• 10 years agoHelpfull: Yes(15) No(0)
• 6*5*4*3=360
• 10 years agoHelpfull: Yes(5) No(8)
• 6p4+2(5p4/2)+4!/(2!2!)= 606
• 10 years agoHelpfull: Yes(5) No(1)
• 8*7*6*5/2!*2!=420
• 10 years agoHelpfull: Yes(5) No(0)
• ans is 606
  
  (2c2*4!/2!2!)+(5c2*2c1*4!/2!)+(6!/4!2!*4!)
• 10 years agoHelpfull: Yes(2) No(1)
• 8!/(2!*2!)
• 10 years agoHelpfull: Yes(1) No(2)
• this May be answers
  
  with repetition of 6 or 5
  
  6*6*5*4*3*2= 4326
  6*5*5*4*3*2= 3600
  
• 10 years agoHelpfull: Yes(0) No(4)
• all distinct = 1,2,3,4,5,6 => 6P4
  2 same 2 distinct = 5,5, 1,2,3,4,6 or 6,6, 1,2,3,4,5 => 2*5C2*(4!/2!)
  2 same 2 same = 5,5,6,6 => 4!/(2!*2!)
  total= 6P4+2*5C2*(4!/2!)+4!/(2!2!)
  =6*5*4*3+5*4*3*4*3+(4*3/2)
  =360+720+6
  =1086
  
• 10 years agoHelpfull: Yes(0) No(2)
• 1.nos containing only 1,2,3,4,5 and 6:6C4x4!=360
  2.nos containing two 5's(Ex:5512):(5C2x4!)/2!=24
  3.nos containing two 6's(Ex:6612):(5C2x4!)/2!=24
  4.nos containing two 5's and 6's(Ex:5566):(4!)/2!x2!=6
  Total nos:360+48+6=414
• 10 years agoHelpfull: Yes(0) No(1)
• can u send some infosys papers related to puzzles
• 10 years agoHelpfull: Yes(0) No(0)