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Numerical Ability
Arithmetic
sum of first 11 terms is x. sum of first 6 terms is y. sum of last 6 terms is z.
What is the 6th term?
Read Solution (Total 15)
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- y+z-x ans
bcoz 1 to 11=x , 1to 6 = y , 6to 11 =z
if
1 to 6 + 6 to 11 =y+z
than 1 to 11 = y+z-6th term
x= y+z-6th
6th = y+z-x
- 10 years agoHelpfull: Yes(28) No(3)
- (x-z-y)?
X is sum of 11 thus x-z=y-6th term
and x-y=z-6th term
so 6th term=x-y-z - 10 years agoHelpfull: Yes(9) No(8)
- x-z=y-6th term
so
6th term=z+y-x - 10 years agoHelpfull: Yes(7) No(0)
- sum of eleven nos/11=x(average)
sum of eleven nos=11x
similarly,
sum of first 6 nos=6y
sum of last 6 n0s=6z
6y+6z=sum of eleven nos+6th no(since 6th no is added twice)
6y+6z=11x+6th no
ANS:6th no=6y+6z-11x - 10 years agoHelpfull: Yes(5) No(4)
- ans -(x-y-z)
becoz 6th term 2 times present in y & z
so 2 times we minus 6th term from x
so ans returned in minus - 10 years agoHelpfull: Yes(3) No(2)
- y+z-x
bcoz 1 to 11=x , 1to 6 = y , 6to 11 =z
if
1 to 6 + 6 to 11 =y+z
than 1 to 11 = y+z-6th term
x= y+z-6th
6th = y+z-x
Read more: http://www.m4maths.com/placement-puzzles.php?SOURCE=TCS&TOPIC=Numerical%20Ability&SUB_TOPIC=Arithmetic#ixzz2uJVcXEWD
Follow us: m4maths on Facebook - 10 years agoHelpfull: Yes(3) No(0)
- if the question is with average not sum then....
First 1-11=x sum=11x
first 1-6=y sum=6y
last 6-11=z sum=6z
first 1-6+last 6-11 =6(y+z)
but in this the value of 6th term twice. so
6th term is 11x-(6y+6z) - 10 years agoHelpfull: Yes(1) No(0)
- sum of first 6 terms a/6=Y=>a=6y
sum of last 6 terms b/6=z=>b=6z
sum of first 11 terms c/11=x=>c=11x
sum of 6 th term is 6y+6z-11x
- 10 years agoHelpfull: Yes(1) No(0)
- bhanu prakash please specify it is AP GP or HP
- 10 years agoHelpfull: Yes(0) No(1)
- sorry question is average of first 11 terms is x.average of first 6 terms is y. average of last 6 terms is y.(not sum it is average)
- 10 years agoHelpfull: Yes(0) No(1)
- ans: y+z-x
- 10 years agoHelpfull: Yes(0) No(0)
- ans : z-x+y
- 10 years agoHelpfull: Yes(0) No(0)
- s11=2a+(11-1)d=x
s6=2a+(6-1)d=y
solving both equations
we get a=(2y-x)/2;d=(x-y)/5
t6=a+(6-1)d
t6=x/2 - 10 years agoHelpfull: Yes(0) No(0)
- 6th term= y+z-x;
- 10 years agoHelpfull: Yes(0) No(0)
- It will be y+z-x
- 10 years agoHelpfull: Yes(0) No(0)
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