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There have 12 basket,7 red balls and 5 white balls,find the probability of getting atleast 1 red ball and 1 blue ball outside the basket or tin
Read Solution (Total 8)
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- 495...(7c3*5c5)+(7c4*5c4)+(7c5*5c3)+(7c6)5c2)+(7c1*5c1)=495
- 10 years agoHelpfull: Yes(5) No(2)
- 12 basket so , probability of choosen 1 basket from 12 basket is :- 12c1
same as prob. of red and blue balls is 7c1*5c1/12c2
and ans is : 12c1*7c1*5c1/12c2 - 10 years agoHelpfull: Yes(3) No(8)
- answer would be= (7c1*5c1)/12c2=35/66
- 10 years agoHelpfull: Yes(3) No(0)
- 5+7=12
12c2=132/2=66
7c1+5c1=7+5=12
66/12=11/2 - 10 years agoHelpfull: Yes(0) No(8)
- 45
10!/8! 2! - 10 years agoHelpfull: Yes(0) No(1)
- (7c1*5c1)/12c2= 35/66
- 10 years agoHelpfull: Yes(0) No(0)
- it is 495
- 10 years agoHelpfull: Yes(0) No(0)
- i think it's an incomplete question....as IN QS it is mentioned 5 white balls but he is asking for finding the probability of BLUE???? baLL.
- 8 years agoHelpfull: Yes(0) No(0)
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