ram can do a work in 36 days Shyam in 54 days and Mohan in 72 days they started working

ram can do a work :36 days
Shyam can do a work : 54 days
Mohan can do a work : 72 days
total unit of work : 216(LCM of 36,54 and 72)
ram can do unit of work per day:6(216/36)
Shyam can do unit of work per day:4(216/54)
Mohan can do unit of work per day:3(216/72)
so equation is: 6*(x-8)(Ram left 8 days before)+4*(x-12)(Shyam left 8 days before)+3*x=216
6*(x-8)+4*(x-12)+3*x=216 => x=24
ans:Mohan will complete the work alone:24 days
10 years agoHelpfull: Yes(3) No(0)
Ram 36 days, Shyam 54 days, Mohan 72 days
Total work to be done 216(Total work done by them must be divisible by 36,54,72)
worker work/day
Ram 216/36 = 6
Shyam 216/54 = 4
Mohan 216/72 = 3
Ram left 8 days before the completion of work 8*3 = 24
Shyam 12 days (12-8) left 4 days before Ram 4*9 =36
they worked 12 days together
mohan can alone complete work for 24 days
10 years agoHelpfull: Yes(1) No(0)
24 days mohan works...
10 years agoHelpfull: Yes(0) No(0)
P > 883 P âˆ’ 7 > 876 The smallest number after 876 that is a multiple of 11 is 880 = 11*80 So P = 11k 7, for some integer k â‰¥ 80 (P 4)(P 15) = (11k 7 4) (11k 7 15) = (11k 11) (11k 22) = 11(k 1) * 11 (k 2) = 121 (k 1)(k 2) Now when k is even, then k 2 is even, so (k 1)(k 2) is even and when k is odd, then k 1 is even, so (k 1)(k 2) is even (k 1) (k 2) = 2n, for some integer n (P 4)(P 15) = 121 (k 1)(k 2) = 121 * 2n = 242n Answer: 3: 242
10 years agoHelpfull: Yes(0) No(1)

ram can do a work in 36 days, Shyam in 54 days, and Mohan in 72 days. they started working together but before the work was to over Ram left 8 days before and 12 days before Shyam. In how many days Mohan will complete the work alone?