One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs. 100/- to buy the balls. How many of each balls he bought?

• Football=3,Cricket ball=41 & Table tennis ball=56
  If Number of Football=x,Cricket ball=y & Table tennis ball=z, then
  x+y+z=100 ---(i) &
  15x+y+0.25z=100 ---(ii)
  Substituting value of z=100-(x+y) from (i) in (ii),we have 59x+3y=300 ---(iii)
  For Equation (iii)satisfies the condition with x=3,y=41
  So z=56
  
• 11 years agoHelpfull: Yes(6) No(6)
• 
  If Number of Football=x,Cricket ball=y & Table tennis ball=z, then
  x+y+z=100 ---(i) &
  15x+y+0.25z=100 ---(ii)
  Substituting value of z=100-(x+y) from (i) in (ii),we have 59x+3y=300 ---(iii)
  For Equation (iii)satisfies the condition with x=3,y=41
  So z=56
  Foot=3,Cricket=41 & tennis ball=56
• 10 years agoHelpfull: Yes(4) No(4)
• football: 3
  cricket ball: 41
  table tennis ball: 56
• 9 years agoHelpfull: Yes(0) No(4)
• suppose we want 100 balls in Rs. - 100. So from here, we got two-equation
  15X+Y+0.25Z=100, and X+Y+Z=100
  after solving these two equations we get X/Z=3/56
  So X = 3 , Z = 56, and Y = 100-X-Y = 41
  3 football , 56 tennis ball , 41 cricket ball
  Let's verify 15*3 + 56*0.25 + 41*1=100 and 3+56+41=100
• 5 years agoHelpfull: Yes(0) No(0)