let exp(m,n)= m to the power n. If exp(10,m)= n*exp(2,2). Then n=?

• 10^m=n*2^2
  i.e 10^m=4n
  so it only possible in case of integer
  if m=2 and n=25
  so 25 answer
• 13 years agoHelpfull: Yes(21) No(9)
• 10^m =n*2^2
  or
  10^m =4n
  n = 10^m/4
  
  Many integer values are possible depending on value of m>1.
• 13 years agoHelpfull: Yes(14) No(2)
• saurav if we take m=3 and n=250 then 1000=1000.... so n can be 250 why only 25 ..... hence as dipin says many integers are possible he is right ....reply for this is welcome
• 13 years agoHelpfull: Yes(3) No(1)
• clearly frm d relation given,
  10^m=n*4
  n=(10^m)/4
  So m will be such that it is divisible by 4.
  therefore value m will be any integer>=2
  and for certain values of m=2,3,4...
  corresponding values of n will be,n=25,250,2500,...and so on
  if u want to solve the series,then u will get "how man solutions are possible"
  
• 12 years agoHelpfull: Yes(1) No(0)
• solution s 2.5
• 13 years agoHelpfull: Yes(0) No(6)
• 10^m=n*exp2^2
  10^m=n*2
  n=10^m/2
• 8 years agoHelpfull: Yes(0) No(1)