If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:
3 - 1 3 + 1

• x^2=9+1+6
  y^2=9+1-6
  therefore x^2+y^2=20
• 10 years agoHelpfull: Yes(12) No(2)
• sorry it is addition then , 2(x^2+y^2)= 40
  hence x^2+y^2 = 20.
  
• 10 years agoHelpfull: Yes(4) No(3)
• 20 is the answer i guess
• 10 years agoHelpfull: Yes(2) No(5)
• (x+y)^2-(x-y)^2 = 6^2-2^2
  2(x^2+y^2)=32
  hence x^2+y^2 =16.
• 10 years agoHelpfull: Yes(2) No(12)
• x=3+1=4
  y=3-1=2
  x^2+y^2=4^2+2^2
  =16+4
  =20
• 10 years agoHelpfull: Yes(2) No(0)
• x^2 + Y^2 = (9+1+6)+(9+1-6)
  = 16 + 4 =20
  ans is 20.
  
• 10 years agoHelpfull: Yes(0) No(0)
• (x+y)^2+(x-y)^2/2=x2+y2
  putting the value of x and y
• 10 years agoHelpfull: Yes(0) No(0)
• (3+1)^2 + (3_1)^2 = 20
• 10 years agoHelpfull: Yes(0) No(0)
• (x+y)²+(x-y)² = x²+y²+2xy+x²+y²-2xy
  = 2(x²+y²)
  (6)²+(-2)² = 2(x²+y²)
  
  Therefore x²+y² = (36+4)/2
  = 18 + 2
• 10 years agoHelpfull: Yes(0) No(0)