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Algebra
28a+30b+31c=365 then find a+b+c?
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- 12
a,b & c are nothing but the months of 28 days,30 days & 31 days in a year
28(1)+30(4)+31(7)=28+120+217=365
So a+b+c=1+4+7=12 - 10 years agoHelpfull: Yes(86) No(0)
- that is great puzzle given by tcs. a=1(for feb)
b=4(april,july,september,november)
c=7(jan,march,may,july,aug,oct,dec)
so a+b+c=12 - 10 years agoHelpfull: Yes(13) No(1)
- 28,30,31 are months in year
in there are 12 months
jan,feb,march,april,may,june,july,aug,spect,oct,nov,dec
in a year there 1month containing 28days
in a year there 4months containing 30days
in ayear there 7months containing 31days
so that 1+4+7=12 i.e a+b+c=12 - 10 years agoHelpfull: Yes(3) No(0)
- 31*5 can make the last digit as 5 of 365. Therefore we got 165 now more 200 can be made by multiplying something that generates 0's at the unit place. Therefore 28*5 and 30*2 will do the rest. The sum of a+b+c generated is 5+2+5 = 12.
- 10 years agoHelpfull: Yes(1) No(7)
- This is like year of calculation for a non leap year
then a=1 ->feb
- 10 years agoHelpfull: Yes(1) No(0)
- great puzzle given in tcs , this is a no of days in evry month of the year
- 10 years agoHelpfull: Yes(1) No(0)
- guyz plz find more puzzels on this web link :http://adityasrmca.blogspot.in/
- 10 years agoHelpfull: Yes(1) No(0)
- my ans is a+b+c=12
- 10 years agoHelpfull: Yes(0) No(3)
- 1+4+7=12 this is my ans
- 10 years agoHelpfull: Yes(0) No(1)
- by using calendars concepts months in ayear 28 days in feb -1 month
31 days in month-7 30days in month-4 total months =12 days =365
so, ans is 12 - 10 years agoHelpfull: Yes(0) No(0)
- ans is 12
represents month in a year
a - 28 1(feb consist of 28 days)
b - 30 4(apr,jun,sep,nov consist of 30 days)
c - 31 7(jan,mar,may,jul,aug,oct,dec has 31 day )
therefore a+b+c = 1+4+7 = 12 - 10 years agoHelpfull: Yes(0) No(0)
- here a=1 b=4 c=7 total 1+4+7=12
means 1 feb of 28days +
4(apr,july,sep,nov) of 30 days +
7(jan,march,may,july,aug,oct,dec) of 31 days=365 days...
- 10 years agoHelpfull: Yes(0) No(0)
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