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what is the weighted mean of first 10 natural numbers whose weights are equal to the corresponding number?
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- = (w1*x1+w2*x2+...+w10*x10)/(w1+w2+...+w10)
= (1*1+2*2+3*3+...+10*10)/(1+2+3+...+10)
= [10*(10+1)*(2*10 +1)/6]/[10*(10+1)/2]
= 7 - 10 years agoHelpfull: Yes(5) No(0)
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