The shadow of a tower standing on a level plane to be 50 m longer when the sun 's altitude is 30 degree than when it is 60 degree.find the height of the tower.
(a)25m
(b)25 sqrt(3)m
(c) 23/sqrt(3)m
(d) 30m

Ans : 25 sqrt(3)m

• H__________________________________
  |60
  |
  |30
  |
  |
  |
  | 60 30
  |-------------------
  _____x__|____50______|
  
  h/x=tan60
  h/x+50=tan30
  solving h=25*(3)^1/3
• 10 years agoHelpfull: Yes(0) No(1)
• let the shadow at 60 degree be x and height =h
  At 60 deg,
  tan 60=h/x
  root3=h/x => x=h/root3;
  
  At 30 deg,
  tan30=h/(x+50) => 1/root3= h/((h/root3)+50)
  
  1/root3=h*Root3/(h+50root3)
  
  => 1= 3h/(h+50root3)
  
  =>3h= h+50root3
  =>2h=50root3
  
  =>h=25root3
  option:(b)
• 10 years agoHelpfull: Yes(0) No(0)
• At 30 deg,
  tan30=h/(x+50) => 1/root3= h/((h/root3)+50)
  1/root3=h*Root3/(h+50root3)
  => 1= 3h/(h+50root3)
  =>3h= h+50root3
  =>2h=50root3
  =>h=25root3
  
• 10 years agoHelpfull: Yes(0) No(0)