Huawei Company Programming Program

main()
{
char p=15;
printf("%d",p++);
}

Read Solution (Total 5)

error
type conversion is not possible to(integer to char)
type conversion only possible for small range to high range.
10 years agoHelpfull: Yes(5) No(0)

Segmentation fault
10 years agoHelpfull: Yes(3) No(0)
segmentation fault (run time error), because pointer always points to address of another variable not value
10 years agoHelpfull: Yes(2) No(0)
error in compilation time
because char can not *p to its value.
10 years agoHelpfull: Yes(0) No(2)
Compilation error ,we can't initialize the character type pointer with integer value.If we do then typecasting is required
10 years agoHelpfull: Yes(0) No(0)

Huawei Other Question

main()
{
printf(3+"Huawei");
} main()
{
static char i;
for(i=0;i<150;i++)
{
printf("*");
}
}