main()
{
static char i;
for(i=0;i<150;i++)
{
printf("*");
}
}

• Infinite times
• 11 years agoHelpfull: Yes(19) No(8)
• Infinte Times.
  I have tested..
• 10 years agoHelpfull: Yes(11) No(0)
• it gives error message
  
  because char range is from -128 t0 127 here 150 exceeds the range
• 10 years agoHelpfull: Yes(7) No(9)
• print * 150 times
• 11 years agoHelpfull: Yes(5) No(10)
• it prints '*' 127 times.After that the value of is incremented by 1,therefore it tries to become 128,which falls outside the valid char range,so it goes to other side and becomes -128 which would satisfy the condition i
• 10 years agoHelpfull: Yes(5) No(0)
• static char i
  initially i=0
  then it will print * 150 times because of for loop.
• 10 years agoHelpfull: Yes(1) No(7)
• 'i' is a character variable. so we need to assign a value by using (''). It will shows compilation error.
• 10 years agoHelpfull: Yes(1) No(4)
• infinite times............tested
• 9 years agoHelpfull: Yes(1) No(0)
• char range is from -128 t0 127,if put i
• 10 years agoHelpfull: Yes(0) No(0)
• when ever we compile this program it prints
  150 times " * "
• 9 years agoHelpfull: Yes(0) No(1)
• how infinite times it will print can any body tell me?
  
• 9 years agoHelpfull: Yes(0) No(0)
• prints * 149 times.
• 9 years agoHelpfull: Yes(0) No(2)
• Infinite Loop
• 9 years agoHelpfull: Yes(0) No(0)
• it gives warning that its out of range
• 9 years agoHelpfull: Yes(0) No(0)
• infinte times
• 9 years agoHelpfull: Yes(0) No(0)
• * will be printed infinite time ...
  i have tested this pgm......
• 9 years agoHelpfull: Yes(0) No(0)
• how can u assign numeric value to char
  
• 9 years agoHelpfull: Yes(0) No(0)
• 150 times * will printed.............i have compile it
• 8 years agoHelpfull: Yes(0) No(0)
• As char "i" is static value of i does change so loop will run infinite times
• 4 years agoHelpfull: Yes(0) No(0)