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Q. A plane travels in the shape of equilateral triangle have sped of 20km/hr, 40km/hr and 60km/hr. Find the average speed of the palne.
Read Solution (Total 8)
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- ave speed = total distance/total time taken
=(d+d+d)/[(d/20)+(d/40)+(d/60)] where d= side of eq. triangle
=3d/d[1/20 + 1/40 + 1/60]
=3*20*40*60/[20*40+40*60+20*60]
= 360/11 km/h
= 32.73 km/h - 10 years agoHelpfull: Yes(54) No(0)
- the average spped when 3 terms are given= 3s1s2s3/(s1s2+s2s3+s1s3)
=3*20*40*60(20*40+40*60+20*60)=360/11 is tha average speed - 10 years agoHelpfull: Yes(40) No(0)
- total distance/total time
=360/11 - 10 years agoHelpfull: Yes(5) No(4)
- 360/11 km/hr
- 10 years agoHelpfull: Yes(3) No(1)
- avg speed = total distance/total time
Ans. 360/11 - 10 years agoHelpfull: Yes(2) No(1)
- 60+40+20/3
120/3
40 km/hr - 10 years agoHelpfull: Yes(1) No(25)
- 3xyz/(xy+xz+yz)
=3*20*40*60/60+80+100
=144000/2400
=60 - 10 years agoHelpfull: Yes(1) No(9)
- ans=32.72
3*d/(d/20+d/40+d/60) - 9 years agoHelpfull: Yes(0) No(1)
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