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Numerical Ability
Age Problem
A cube is cut into 216 parts. the 2nd 4th n 6th layers of the front face r removed n den painted
black. Now answer d following questions.
1) How many cubes r painted on only one side?
2) How many cubes r painted on only 2 sides?
3) How many cubes r painted on only 3 sides?
4) How many cubes r painted on only 4 sides?
5) How many cubes r painted 0 sides?
Read Solution (Total 11)
-
- No. of cubes=(sides)^3
then,216=(sides)^3
sides=6
In cube total six face but in ques 3 face r removed then only 3 face r there.
no of cubes painted only one side=(x-2)^2* no. of faces
=(6-2)^2*3
=48
no of cubes painted only 2 sides=(x-2)*no. of edges
=4*12
=48
no of cubes painted only 3 sides=8 always
because there are 8 corner in cubes
no.of cubes painted 0 sides=(x-2)^3
=4^3=64
but in 4 sides i dont know.
- 10 years agoHelpfull: Yes(19) No(2)
- let n be the sides
216 =n^3
6^3=n^3
so n=6
and friends these are the direct formula to know number of sides painted
o sides painted--->(n-2)^3
1 side painted---> 6(n-2)^2
2 sides painted--->12(n-2)
3 sides painted--->8
for 4 sides i dont know ..
- 10 years agoHelpfull: Yes(7) No(3)
- 1.96
2.48
3.8
4.0
5.64 - 10 years agoHelpfull: Yes(6) No(2)
- 1. 2[4+4+16]=48
2. 2[16+2]=36
3. 8
4. 0
5. 16 - 10 years agoHelpfull: Yes(5) No(4)
- 1.96
2.48
3.8
4.0
5.64 - 10 years agoHelpfull: Yes(4) No(1)
- 1=80
2=24
3=4
4=0
5=108 - 10 years agoHelpfull: Yes(1) No(1)
- 1 ans 68=12+12+16+16+12
- 10 years agoHelpfull: Yes(0) No(1)
- consider tht layers are painted after removal of the layers in between them..
1)0
2)48
3)48
4)12
5)0 - 10 years agoHelpfull: Yes(0) No(1)
- pls tell the correct answer ... @moumitabhakat is the formulae and the ans ryt??..just let me know thnku
- 10 years agoHelpfull: Yes(0) No(1)
- 1.0
2.48
3.48
4.12
5.108
- 10 years agoHelpfull: Yes(0) No(1)
- 2faces painted=4x12=48
3faces painted=8
1face painted=16x6=96
0face painted=total edge-(sum of all side painted) =216-(8+48+96)=64 - 6 years agoHelpfull: Yes(0) No(0)
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