there are 4 chairs. among 6 men and 4 women , 2 men and 2 women are to be seated on the chairs then what is the probability of them to be seated.

• 6c2*4c2=90
  
• 10 years agoHelpfull: Yes(2) No(3)
• 6c2*4c2/10c4=3/7 ans...
• 10 years agoHelpfull: Yes(1) No(0)
• men,6c2=15 combinations..i.e 30 men.
  women,4c2=6 combinations..i.e.12 women.
  so,for each of them to be seated from their respective men
  and women category,each of men has probability of 2/30=1/15=0.06,whereas in that case of each of women will go with 2/12=1/6=0.16
• 10 years agoHelpfull: Yes(0) No(0)
• 6c2*4c2/10c4=3/7
• 10 years agoHelpfull: Yes(0) No(0)