4 male and 6 female can cultivate a field in 8 days, 7 male and 3 female can cultivate a field in 10 days. then how many days will take to cultivate a field if 10 female works?

• 4 male+6female in 8 days=> 32 male+48 female in 1day
  7male+ 3 female in 10 days =>70 male+30 female in 1 day
  .:32 male+48 female=70 male+30 female
  18 female=38 male
  1 female= 38/18 male=19/9 male
  now,4 male+6 female=4 male+6*(19/9)=50/3 male=150/9 male
  we have to find for 10 female workers= 10*(19/9)=190/9 male
  more men ,fewer days wud be req to finish work
  male days
  150/9 8
  190/9 x
  
  so, x/8=(150/9)/(190/9)
  
  x=120/19
  
• 10 years agoHelpfull: Yes(29) No(3)
• 4x+6y=1/8
  7x+3y=1/10
  then, solving we get
  y=19/(40*30)
  for 10female.. (19*10)/(40*30)days..
• 10 years agoHelpfull: Yes(28) No(6)
• 4m+6f=(1/8)
  7m+3f=(1/10)
  f=76/4800
  10 female work=10(76/4800)=76/480
  days=480/76=120/19
• 10 years agoHelpfull: Yes(13) No(3)
• 4 male+6female in 8 days=> 32 male+48 female in 1day
  7male+ 3 female in 10 days =>70 male+30 female in 1 day
  .:32 male+48 female=70 male+30 female
  18 female=38 male
  1 female= 38/18 male=19/9 male
  now,4 male+6 female=4 male+6*(19/9)=50/3 male=150/9 male
  we have to find for 10 female workers= 10*(19/9)=190/9 male
  more men ,fewer days wud be req to finish work
  male days
  150/9 8
  190/9 x
  
  so, x/8=(150/9)/(190/9)
  x= 40/3 days
• 10 years agoHelpfull: Yes(5) No(6)
• 4m+6f=8 (1)
  7m+3f=10 (2)
  for 1 day
  32m+48f=1 (3)
  70m+30f=1 (4)
  equating eq 3 nd 4
  32m+48f=70m+30f
  m=9/19f
  from eq 1, we have
  4*9/19f+6f=8
  150/19f=8 (5)
  M1*D1=M2*D2
  150/19*8=10*D2
  D2=120/19
  
• 10 years agoHelpfull: Yes(2) No(2)
• 4x+6y=1/8
  3x+7y=1/10
  & on solving both equestin we get y=1/400
  so for 10 female its 10*1/400=1/40 i.e 40 days answer
• 10 years agoHelpfull: Yes(2) No(1)
• 120/19 It is 13 days
• 10 years agoHelpfull: Yes(1) No(4)
• let the number of males=x;
  number of females=y and
  the number of days to be found=z;
  let the 1st equ be 4x+6y=8;
  2nd equ be 7x+3y=10;
  3rd equ be 10y=z;
  solving the equ 1 and 2, we get x=6/5;
  sub x in equ 2 we get y=8/5;
  sub y in equ 3 we get z=16;
  
  so the number of days=16
  
• 10 years agoHelpfull: Yes(1) No(4)
• 4 male+6 female=4 male+6*(19/9)=50/3 male=150/9 male
  here how 150/9 becomes? why multiply (50/3)*(3/3)
• 10 years agoHelpfull: Yes(1) No(1)
• ans.48/7 days.
  equation,
  4*8*x+6*8*y=z...-->1
  7*10+3*10*y=z...-->2
  x+y=1,
  x=9/23,
  y=14/23,
  z=960/23.
  
• 10 years agoHelpfull: Yes(0) No(6)
• 4m+6f=1/8
  7m+3f=1/10
  
  
• 10 years agoHelpfull: Yes(0) No(4)
• 120/19=6.315 approximately 7 days
  
• 10 years agoHelpfull: Yes(0) No(2)
• 4m+6f=8days------------ eq 1
  7m+3f=10days----------- eq 2
  solving eq 1 and 2 we gwt
  f= 0.5333
  we need 10f= ? ------------ eq 3
  substitute f in eq 3
  we get 5.3 days
  answer : 5.3 days
• 10 years agoHelpfull: Yes(0) No(0)
• i think 20 days
  
• 9 years agoHelpfull: Yes(0) No(0)