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Numerical Ability
Sequence and Series
Q. COMPLETE THE SERIES..
1, 3, 7, 11, 13,... ?
Read Solution (Total 16)
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- i think in this series we need to divide series in two parts i.e in terms of even place term and odd place term.i.e
1,7,13 so in odd term you see a difference of 6.
and in even terms there is difference of 8
3,11 so next term will be 11+8=19.
so series is like this
1,3,7,11,13,19. - 10 years agoHelpfull: Yes(31) No(8)
- 1^2-0=1
2^2-1=3
3^2-2=7
4^2-3=13
5^2-4=21 - 10 years agoHelpfull: Yes(31) No(25)
- difference between numbers i think
3-1=2
7-3=4
11-7=4
13-11=2
so,
next numbers is 17
because 17-13=4
21-17=4
23-21=2
so ans is 17.
its right or not.plz reply - 10 years agoHelpfull: Yes(19) No(14)
- answer is 17
1,3,7,11,13...
1 3 7 11 13 17
+2 +4 +4 +2 +4 - 10 years agoHelpfull: Yes(9) No(4)
- Ans is 17 since all are prime numbers written in ascending order
- 10 years agoHelpfull: Yes(8) No(5)
- this is a series of prime numbers.
The next prime number after 13 is 17 .
hence 17 is the answer. - 10 years agoHelpfull: Yes(4) No(7)
- ans is 17
here series is getting added with 2,4,4,2,4,4 and its repeating like that.
1+2=3
3+4=7
7+4=11
11+2=13 series is repeating here again
so next term is 13+4=17 - 10 years agoHelpfull: Yes(2) No(1)
- 17
13+4=17
the diff. in series is 2,4,5 and thn 2 - 10 years agoHelpfull: Yes(1) No(3)
- which is the correct answer 21 or 17
- 10 years agoHelpfull: Yes(1) No(1)
- neha there 11 is missing..ans is 17
- 10 years agoHelpfull: Yes(1) No(0)
- ans is 19 the series has two series 1,7,13 diff=6
3,11.. diff =8
so ans is 11+8=19
- 10 years agoHelpfull: Yes(0) No(3)
- it is the series of odd prime numbers, so next number must be 17
- 10 years agoHelpfull: Yes(0) No(0)
- 1 3 7
11 13 17
- 10 years agoHelpfull: Yes(0) No(0)
- all prime no. is in assecending order so ans is 17 .
2nd explanation
diff is in order 2 ,4 ,4,2 so next no. will be 13+4=17 - 8 years agoHelpfull: Yes(0) No(0)
- 2 & 4 add so next is 17
- 8 years agoHelpfull: Yes(0) No(0)
- 1 3 7 11 13 17
+2 +4 +4 +2 +4 - 4 years agoHelpfull: Yes(0) No(0)
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