A can do as much work as C in 2 days and C does in 3 days as much work as B in 4 days. What time B would require to do a work which A can do in 16 weeks?

• let A,B,C works is x,y,z
  so 1/x=2/z---(I)
  3/z=4/y-------(II)
  
  1/x=1/16---(III)
  from all the euatn
  z=3*y/4
  so 1/x=8/3*y
  
  1/16= 8/3*y
  y=16*8/3 weeks
• 10 years agoHelpfull: Yes(20) No(1)
• efficiency of A:C=2:1.
  efficiency of C:B=4:3.
  So, efficiency of A:C:B=8:4:3.
  so efficiency of A:B=8:3.
  so time taken by A:B=3:8=16:B
  ===>B=(128/3)=42*(2/3) weeks.
• 8 years agoHelpfull: Yes(10) No(0)
• A(2 day's work)=c(3 day's work)
  A(16*7 days work)=c(3*16*7/2)day's=168 days
  C(3 Days work)=B(4 day's work)
  C(168 Day's work)=B(4*168/3)=224 Days
• 10 years agoHelpfull: Yes(9) No(13)
• 298.66 DAYS
  
• 8 years agoHelpfull: Yes(3) No(1)
• A = 2C
  3C=4B
  C=(4/3)B
  A=2*(4/3)B=(8/3)B or B=(3/8)A
  A can do a piece of work in 16*7 days.
  (3/8)A can do the sme piece of work in --------
  (less/more)*(16*7)
  ((3/8)A)/A*(16*/7)=21days=3weeks.
  
• 9 years agoHelpfull: Yes(2) No(2)
• a:b = 2:1
  b:c=4:3
  so , A:B:C = 2:4:3
  Now acc to question ,
  a:b = 2:4
  and
  the weeks are 16 ,so days is 16*7=112 days
  so , diff btw ratio of a:b is 2 .so divide 112/2 = 56
  now multiply ratio of A&B with 56
  a:b = 2:4
  =>2*56 : 4*56
  112 days(16 weeks) : 224 days (32 weeks )
  so the answer is 32weeks i.e 224 days
  its by efficiency method
• 8 years agoHelpfull: Yes(1) No(1)
• A can do as much as wrk in 2 days so A:C=1:2,In the same way they have compared C and B,so C:B=3:5...Taking B as 20(Assumption 4*5)...C would be 12(4*3)...hence 12C:20B(C:B) As per ratio given..then take12C with respective to A(A:B)...then the 12C is 2 part in 1:2 and 1 is 6..so 6A:12C:20B.....so ans is more than 55 weeks
  
• 10 years agoHelpfull: Yes(0) No(2)
• correct answer is 42 week 4 days
• 9 years agoHelpfull: Yes(0) No(2)
• A's 1 week work=1/16
  C's 1 week work=1/32
  B's 1 week work=3/(32*4)
  B complete the work in 128/3 week.
• 8 years agoHelpfull: Yes(0) No(2)
• The % of Work Done By A=100/20=5% in one Minute.
  The % of Work Done By B=100/30=3.33% in one Minute.
  The % of Work Done By C=100/15=6.67% in one Minute.
  Hence % of Work Done By A+B+(-C) in one Minute=5+3.33-6.66=1.67%
  How Soon Cistern be filled =100/1.67=59.88
  minutes=59.88*3=179.6 minutes=180 minutes.
• 8 years agoHelpfull: Yes(0) No(3)
• radius would be r/5 and height would h/5 , and the variable term is sqr(r)*h and hence 25*5=125 . Therefore ans is - 1:125
• 6 years agoHelpfull: Yes(0) No(0)
• person A B C
  days 2 4 3
  L.c.m of 2,4,3 is 12
  so cosider 12 units of work
  A can do 12/2=6 units in a day
  B can do 12/4=3 units in a day
  c can do 12/3=4 units in a day
  A in 1 day can do 6 units of work, so in 16 weeks A can do 16*7*6=672 units.
  B in 1 day can do 3 units of work,so 672 units in 672/3=224 days(32 weeks)
• 6 years agoHelpfull: Yes(0) No(0)