Elitmus Exam Numerical Ability Time and Work

To do a piece of work , B takes 3 times as long as A and C together and C takes twice as long as A and B together. If three together can complete the work in 10 days, how long would A take by himself?

Read Solution (Total 1)

24 days
If days to complete the work by A,B & C are x,y & z respectively
So 1 day work of A,B & C= 1/x, 1/y & 1/z respectively
Given 3/y=[(1/x)+(1/z)] ---(i)
2/z=[(1/x)+(1/y)] ---(ii) &
(1/x)+(1/y)+(1/z)=1/10 ---(iii)
Solving (i),(ii) & (iii), x=24,y=40,z=30
10 years agoHelpfull: Yes(31) No(9)

Elitmus Other Question

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