A,B and C can do a piece of work in 12,18, and 24 days respectively. they work at it together . A stops the work after 4 days and B is called off 2 days before the work is done.In what time was the work finished?

• If A can do a piece of work in 12 days then in one day he can do 1/12 work.
  
  Similarly, B's one day work is 1/18
  
  and C's one day work is 1/24.
  
  Here it tells about the no of days A and B worked but its not telling anything about C.
  
  So, lets assume C work for x days.
  
  then, B work for x-2 days(as it given that he left the job 2 days before completion)
  
  and, A work for 4 days(as given in the question)
  
  Therefore, A's work + B's work + C's Work = 1
  
  4/12 + x-2/18 + x/24 = 1
  
  After solving,
  
  x = 8 days.
  
  Therefore, we assumed that C worked for x days means C is the only one who worked till the last day. Therefore x=8 is the required answer.
  
  Therefore, the total work was finished in 8 days.
• 10 years agoHelpfull: Yes(62) No(3)
• percentage of work done by A=(1/12)*100=8.33%
  similarly B=5.55%
  C=4.16%
  WORK DONE IN 4 DAYS=4(8.33+5.55+4.16)=72.16% (APPROX)
  WORK DONE BY C ALONE IN LAST 2 DAYS=2*4.16=8.32%
  WORK LEFT TO BE DONE=100-72.16-8.32=19.52%
  THIS IS TO BE DONE BY BOTH B AND C SO NO OF DAYS REQUIRED=
  19.52/(5.55+4.16)=2 DAYS(APPROX)
  HENCE TOTAL DAYS= 4(DONE BY ALL)+2(DONE BY B AND C)+2(C ALONE)=8DAYS
  
• 10 years agoHelpfull: Yes(12) No(1)
• ans:-8 days
  
  A's work - 1/12
  B's work - 1/18
  C's work - 1/24
  
  all of them worked at it for 4 days so total work:-
  4(1/12+1/18+1/24)=26/36
  
  now,
  remaining work is 1-(26/36)=5/18
  
  Now suppose that both B and C take 'x' days to complete a work of 5/18
  (It is given that B is called off 2 days before the work is done)
  
  thus,
  (x-2)/18+(x/24)=5/18
  solving we get x=4
  So,
  (B and C worked at it for 2 days followed by 2 days work of C alone)
  to these 4 days we add previous 4 days of working of all of them together...
  
  Thus
  4 days (A+B+C) + 4 days((2 days B+C) + 2 days of C alone) = 8 days..
  
  8 days
• 10 years agoHelpfull: Yes(10) No(0)
• A work 4/12 in 4 days=1/3
  so left work =2/3.
  now let work is completed in x days then,
  (x-2)/18+x/24=2/3.
  x=8.
  
  
• 10 years agoHelpfull: Yes(7) No(0)
• 8 days(4+2+2)
• 10 years agoHelpfull: Yes(3) No(4)
• A---12
  B---18
  C---24
  LCM of these 3 is 72
  units of work done by A----6
  units of work done by A----4
  units of work done by A----3
  
  NOW, 6+4+3=13
  
  they all worked together 4 days in the starting so 13*4=52
  
  so work remaining after 4 days=72-52=20
  means 20units of work is remaining
  
  now B left before 2 days so total unit of work remaing will become (4*2)+20=28
  
  so no. of days=28/(4+3)=4 days
  
  and the days they worked together=4 days
  
  so total days=4+4=8 days
• 10 years agoHelpfull: Yes(2) No(0)
• 4 days (A+B+C) + 4 days((2 days B+C) + 2 days of C alone) = 8 days.
  
• 10 years agoHelpfull: Yes(1) No(0)
• 8 days
  Total work-72
  A-12(6)
  B-18(4)
  C-(3)
  A+B+C=(6+4+3) *4=52(for 4 days)
  Then remaining work 72-52=20
  B left the work 2 days before done
  That means C works alone 2 days
  2*3=6
  Then remain work=20-6=14
  14 work done by B+C=14/2=7
  That is total days =4+2+2=8
• 3 years agoHelpfull: Yes(0) No(0)