One pendulum ticks 57 times in 58 sec and another 608 times in 609 sec. If they started simultaneously then find the time after which they will tick together.

• LCM of 58/57 and 609/608 sec will be 1218/19.
  lcm of (58,609)is 1218
  hcf of (57,608) is 19
  Ans:1218/19==64.1 secs
• 10 years agoHelpfull: Yes(23) No(0)
• first take the hcf of 57 and 608 and then take the lcm of 58 and 609 then divide the lcm by hcf
  
• 10 years agoHelpfull: Yes(11) No(0)
• can any one please explain it clearly....
• 10 years agoHelpfull: Yes(3) No(1)
• 58*609/lcm of 57,608=19
  ans=1859sec=30mts 59 sec
• 10 years agoHelpfull: Yes(2) No(7)
• can any 1 explain with lcm & hcf
• 10 years agoHelpfull: Yes(0) No(1)
• 58/57,609/608
  Upper is 58,609 take lcm
  Lower is 57,608 take hcf
  Lcm of 58,609=29,2,21
  Hcf of 57,608=19
  Ans:1218/19=64.1sec
• 4 years agoHelpfull: Yes(0) No(0)