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Time Distance and Speed
Without stoppages a train travels a certain distance with an average speed of 80 km/h and with stoppages with an average speed speed of 60 km/h. How many minutes per hour does the train stops ?
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- stoppage time per hr=(change in speed)/(faster speed) hr
=20/80=1/4 hr=15min - 10 years agoHelpfull: Yes(66) No(0)
- the ans is 15 mins
let us assume the distance is x km.
if the train travels 80km/h without stopages then it takes (x/80) hour to rech.
and with stopage it takes (x/60) hour.
let the train stops t min per hour.
then according to the question
(x/80)=(x/60)+(t/60)*(x/60)
then t=15 min. - 10 years agoHelpfull: Yes(18) No(3)
- Here, distance to be covered is constant
Hence, using the formula
Stoppage time/hour = Change is speed/ Faster Speed
=(80-60)/80 hr
=1/4 hr
==>15 minutes - 10 years agoHelpfull: Yes(6) No(0)
- ans is 15..(dif in speed /highst spd) *60
- 10 years agoHelpfull: Yes(2) No(0)
- Ans:20 minutes
D1=D2
S1*T1=S2*T2
80*60=60*(60+x)
where x is the stoppage time,
4800=3600+60x
x=20min. - 10 years agoHelpfull: Yes(0) No(16)
- time=dif in speed/ speed of excluded condition*60 mints =(20/80)*60
or 80 km-60mint
20km-? ?=20*60/80=15...
- 10 years agoHelpfull: Yes(0) No(0)
- time of train/hrs=difference in avg. speed/speed without stopage
=80-60/80=1/4
=15 min - 9 years agoHelpfull: Yes(0) No(0)
- Due to stoppages, it covers 20 km less.
Time taken to cover 20 km =(20/80) * 60
=15 minutes
- 9 years agoHelpfull: Yes(0) No(0)
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