6 Bangles eachof 4 cm in diameter,what is their minimum diameter of the plate required so that each of bangles are kept without overlapping(bangles touching each other)?

• place one bangle at the center and the remaining 5 bangles surrounding them, so
  
  minm dia of plate red = sum of dia of three bangles = 4+4+4 = 12cm
  
• 10 years agoHelpfull: Yes(36) No(1)
• ans is 12 cm
  for min diameter of plate all bangle place in shape of hexagon so side of hexagon is 4 cm and radius of place 4+2 (add radius of bangle )
  so diameter is 12 cm ans....
• 10 years agoHelpfull: Yes(2) No(0)
• ans=5 (if we need an integer diameter otherwise root of 24)
  area of 6 bangles=pie*2*2*6=24pie
• 10 years agoHelpfull: Yes(1) No(2)
• 12cms is the min diameter....
• 10 years agoHelpfull: Yes(1) No(0)
• @mohan lal y cant we place bangle in middle???and y u make hexagon..it also be possible that u make pentagon and keep sixth bangle in middle..
• 10 years agoHelpfull: Yes(0) No(2)
• hai rakesh,why consider sum of 3 bangles?
• 10 years agoHelpfull: Yes(0) No(3)
• ans. is
  
  4root2
• 10 years agoHelpfull: Yes(0) No(0)
• Please suggest the correct solution of this question..
  
• 9 years agoHelpfull: Yes(0) No(0)
• I it should be 8 .
  all the five bangles can be put half of the plate and the reaming one in center of all.
  min. diameter of plate 2+4+2 = 8
• 8 years agoHelpfull: Yes(0) No(0)
• One bangle at the center and the remaining 5 surrounding them, so radius of the center +the diameter of the outer bangle = 4+2=6cms
• 8 years agoHelpfull: Yes(0) No(0)