Three dices rolled . what is the probability of getting atleast one six.
Option
a) 1/6*5/6*5/6
b) 3*1/6*5/6*5/6
c) 5/6*5/6*5/6
d) none

• probability of getting atleast one siz is 1-Probability if no six.
  hence 1- 5/6*5/6*5/6
• 10 years agoHelpfull: Yes(30) No(0)
• none... as prob. of getting 1 six is 1/6*5/6*5/6 two six is 1/6*1/6*5/6..three six is 1/6*1/6*1/6 and answer will be their sum. so none(ans)
• 10 years agoHelpfull: Yes(9) No(1)
• none.....answer is 1-(5/6+5/6+5/6)=91/216 so "d" option
• 10 years agoHelpfull: Yes(3) No(2)
• And=*, OR=+ (1/6&5/6&5/6) OR (1/6&1/6&5/6) OR (1/6&1/6&1/6)= 31/216.
  So,Ans is d.
• 10 years agoHelpfull: Yes(2) No(0)
• AS Bionomial Distribution Formula:P(x=r)=nCr*p^r*(1-p)^r
  p=sucess in A single trial.
  q=Unsucess in a single trial(q=1-p)
  ATQ:probablity of getting Six in singal trial p=1/6 nd q=5/6
  given no dice rolled=3(n)
  X=event of getting six.
  nw we have calculate P(X>=1)=1-P(x=0)
  P(X>=1)=1-(3C0*(1/6)^0*(5/6)^(3-0)).
  P(X>=1)=1-((5/6)*(5/6)*(5/6))
  
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• ans is c.
  Multiply the chances of NOT getting a six(5/6) on the first die by the chances of NOT getting a six on the second die (5/6) by the chances of NOT getting six on the third die(5/6), and the subtract the whole thing from 1.
  
  1 - (5/6 x 5/6 x 5/6) = 0.5787
  
• 10 years agoHelpfull: Yes(1) No(0)
• answer is "b"
  question demands for atleast one six.
  Prob of getting 6 in 1st dice X prob of not gettng six in 2nd dice X prob of not gettng six in 3rd dice
  similarly,
  not getting in 1st dice X getting in 2nd dice X not getting in 3rd dice
  not getting in 1st X not gettng in 2nd X getting in 3rd
  
  thereforem,
  3(1/6*5/6*5/6) is correct
  
• 10 years agoHelpfull: Yes(1) No(4)
• SOrry above formula has missing some term
  correct one is P(x=r)=nCr*p^r*(1-p)^(n-r)
• 10 years agoHelpfull: Yes(1) No(0)
• (6+other+other)+(6+6+other)+(6+6+6)
  (1/6*5/6*5/6)3!/2!+(1/6*1/6*5/6)3!/2!+(1/6*1/6*1/6)3!/3!
  75/216+25/216+1/216
  91/216
• 9 years agoHelpfull: Yes(1) No(0)