Elitmus
Exam
Numerical Ability
Ratio and Proportion
Q. Dhaniram lights a Agarbatti each morning and stops it at 1/3rd of its length. After how much days he will be left with 10% of the original height of agarbatti.
Options
a) 2
b) 3
c) 4
d) cannot be determined
Read Solution (Total 4)
-
- let us say length x
1st mrng x/3
2nd mrng(x/3)*(1/3)=x/9
10% of original height means x/10
3 rd mrng =x/27
so answer 2 - 10 years agoHelpfull: Yes(14) No(6)
- can not be determine until aur unless the length of the agarwatti is not give because solving questin this depend on x so we cannot determine
- 10 years agoHelpfull: Yes(10) No(9)
- let length of agarbatti be x.
use alligations formula,
x(1-fraction of agarbatti reduse)^t =x*10/100
=> x(1-1/3)^t = x*10/100
=> (2/3)^t = 10/100
taking log on both side
t(log(2/3))=log(10/100)
solve it............ - 10 years agoHelpfull: Yes(4) No(0)
- cannot determine as after 3rd day it is 1/27 so cannot find days
- 10 years agoHelpfull: Yes(0) No(1)
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