k1= -19 k2= -139/3 such that Kj=Kj-1 – Kj-2 . j is in sub script. Find the 602nd term of such a sequence.

• Ans:- -139/3
  
  according to sequence given
  K1= -19
  K2= -139/3
  K3= -82/3
  K4= 57/3
  K5= 139/3
  K6= 82/3
  K7= -19(repeats)
  .
  .
  .
  K601= -19
  K602= -139/3
• 10 years agoHelpfull: Yes(19) No(2)
• k602=-139/3
• 10 years agoHelpfull: Yes(0) No(6)
• k1=-19
  k2=-139/2
  k3=-101/2
  k4=19
  k5=139/2
  k6=101/2
  .
  .
  .
  .
  .
  .k100=-19
  k101=-139/2
  k102=-101/2
  .
  .
  .
  . n so on...
• 10 years agoHelpfull: Yes(0) No(2)
• hai shahid,i can't understand please explain
  how to become
  k3=-82/3
  .
  .
  .
  k602=-139/3
• 10 years agoHelpfull: Yes(0) No(1)