X=W^2+1 such that 121

• X=W^2+1 such that 121 < X < 1331 (11^3=1331).what cannot be the remainder when X is divided by 11 provided X is not a prime number
  Option 2/4/6/8
  
• 10 years agoHelpfull: Yes(4) No(0)
• X=W^2+1 & 11^2 < x < 11^3
  
  its easy to check from options
  if w=12, x=145, x/11 => rem=2
  if w=13, x=170, x/11 => rem=4
  if w=14, x=197(prime)
  if w=15, x=226, x/11 => rem=6
  
  thus we see x/11 gives remainder 2,4,6
  
  ans: 8 can't be remainder
• 6 years agoHelpfull: Yes(2) No(0)
• Let w=12 soo, X=12^2+1=144+1=145
  145/11=2 remainder
• 10 years agoHelpfull: Yes(1) No(1)