Elitmus
Exam
Logical Reasoning
General Mental Ability
Data Sufficency
Find y
I.(X-4)=1
Ii.(X-4)(Y-4)=0
Read Solution (Total 14)
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- only 2nd is sufficient to find y
from 1st, (X-4)=1 => x=5
whatever be value of x,2nd statement gives value of y=4
no need to find x from 1st , if x=6,7,8,... then also y=4
(X-4)(Y-4)=0 =>(y-4)=0 => y=4
- 10 years agoHelpfull: Yes(37) No(30)
- Both statements are required.
If statement I is not given, then x can be equal to 4 and y can have any value.
as x-4=1; in that case only , y has unique value ; i.e. y=4 - 10 years agoHelpfull: Yes(35) No(12)
- both statement are required . because if first statement is not given then two case arises :-
x-4=0 or y-4=0 - 10 years agoHelpfull: Yes(11) No(2)
- Only second is sufficient because..
(X-4)(Y-4)=0
=> Y-4=0 (X-4 goes to the right side and becomes 0)
Y=4 - 10 years agoHelpfull: Yes(4) No(7)
- (x-4)(y-4)=0 means that (x-4)=0 and (y-4)=0 . Therefore y=4 The second is alone sufficient to answer
- 10 years agoHelpfull: Yes(4) No(3)
- only 2 is sufficiant
- 10 years agoHelpfull: Yes(3) No(0)
- hai rakesh, i think both statment is required.because,
put (X-4)=1 in second.i.e.,
(X-4)(Y-4)=0
1(Y-4)=0
y=4 - 10 years agoHelpfull: Yes(2) No(1)
- when x-4=1
x=4+1
x=5
put value of x=5 in eq 2
1.y-4=0
y=4 - 10 years agoHelpfull: Yes(1) No(1)
- both statements are required
bcoz, 1st we solve I) X-4=1 i.e X=5
Then substitute the value of X in II)
So, (5-4)(y-4)=0 => 1.(y-4)=0 => y=4
- 10 years agoHelpfull: Yes(1) No(1)
- Both I and II together give the solution....
- 10 years agoHelpfull: Yes(1) No(0)
- x=5
put the value of x in 2nd part y=4 - 10 years agoHelpfull: Yes(0) No(1)
- both are required. if x=4, then y can have any value.
- 10 years agoHelpfull: Yes(0) No(1)
- both 1 and 2 give answer
- 10 years agoHelpfull: Yes(0) No(1)
- Both are required as with the second either x-4 is 0 or y-4 is 0 or both but using eq 1 it is ensured that y-4 is 0
- 10 years agoHelpfull: Yes(0) No(1)
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