Q. How many 5 digit no. can b formed with digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not repeated

• for a no. to be divisible by 4, last two digit should be divisible by 4
  last tw0 digit can be 12,16,24,32,36,52,56,64 (8 possibilities)
  remaining 3 places can be filled in 4*3*2 ways for each
  
  total 5 digit no. formed = 8*4*3*2 = 192
• 10 years agoHelpfull: Yes(39) No(2)
• 6._ _ _ 5 2
  7._ _ _ 5 6
  8._ _ _ 6 4
  2*3*4*8=192
• 10 years agoHelpfull: Yes(3) No(1)
• we have to form 5 digit number by using digit 1,2,3,4,.5,6
  so as it is divisible by 4,
  therefore last two digit will be 12,16,24,32,36,52,56,64
  rest place will be filled by four no.
  i.e. 4*3*2=24
  and by taking last two digit number there wil be 8 number
  therefore
  8*4*3*2=192
• 10 years agoHelpfull: Yes(2) No(1)
• ans:120
  cases :
  1. _ _ _ 1 2 =>2*3*4=24
  2. _ _ _ 1 6 =>2*3*4=24
  3. _ _ _ 2 4 =>2*3*4=24
  4. _ _ _ 3 2 =>2*3*4=24
  5. _ _ _ 3 6 =>2*3*4=24
  ________________________
  -------------=>24*5=120
• 10 years agoHelpfull: Yes(0) No(9)
• ending 2 digits must be multiple of 4 such combinations are
  42
• 10 years agoHelpfull: Yes(0) No(6)