1) Find the number lying between 900 and 1000 which when divided by 38 and 57 leaves in each case a remainder 23.
A) 912
B) 926
C) 935
D) 962

• option c)935 is the answer
  
  using option and checking for a multiple of 38 we find that 38*24=912.
  Now subtract 912 from each options to check for a remainder 23. this will suffice the remaining case also as only one option is satisfying the condition.
• 10 years agoHelpfull: Yes(3) No(0)
• 935
  
  LCM of 38,57 is 114
  So multiples 114, 228, 342, 456, 570, 684, 798, 912, 1026.........are divisible by 38,57
  912+23 => 935 gives reminder 23
  
• 9 years agoHelpfull: Yes(1) No(0)
• x*38+23=A or B or C or D
  Here, 38*24=912
  912+23= 935(Ans.)
• 10 years agoHelpfull: Yes(0) No(0)