the length of each of the two equal sides of an isosceles triangle is 10 cm and the included angle betweeb those two sides is 45 degree.Find the area of the triangle?

• Area of triangle When two sides and angle included between them is given.SAS method.
  Area=1/2*a*b Sin C
  =>1/2*10*10*Sin 45
  =>35.4cm^2
• 10 years agoHelpfull: Yes(4) No(0)
• For Isosceles triangle both the angles is equal. Means angle between 2 equal arm is 90 degree.
  So, area= 1/2*10*10=50
• 10 years agoHelpfull: Yes(0) No(0)
• Sin 45°= perpendicular/hypotenuse
  1/√2 = x/10
  x= 10/√2
  Then
  Area of triangle = 1/2*b*h
  = 1/2*10*10/√2
  =50/√2
  =50*√2/√2*√2(both side multiply root 2)
  =50*√2/2
  =25√2
• 7 years agoHelpfull: Yes(0) No(0)