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33. 17 x 8 m rectangular ground is surrounded by 1.5 m width path. Depth of the path is 12 cm. Gravel is filled and find the quantity of gravel required.
a. 5.5
b. 7.5
c. 6.05
d. 10.08
Read Solution (Total 13)
-
- area of the rectangular ground=(17*8)m^2=136 m^2
taking into account the path:
total area=[(17+(2*1.5))*(8+(2*1.5))]=220 m^2
area of the path=220-136=84m^2
gravel required=[84*(12/100)]=10.08m - 10 years agoHelpfull: Yes(45) No(1)
- The area covered by the path around the rectangle= 2(1.5*17)+2(1.5*8)+4(1.5*1.5)=84 m2.
Now, Quantity of gravel filled=Volume of the path=84*0.12=10.08 m3. Answer is (d). - 10 years agoHelpfull: Yes(9) No(6)
- area of ground initially : 17*8 =136 sq m
when 1.5 m width path is included length and breadth increases by 2*width i.e. 3 m...so new
lenth and width becomes 17+3 and 8+3 i.e. 20m and 11m..now area of new porion = 20*11 = 220 sq m.
area under gravel = new area - original area = 220-136 = 84 sq m.
now amount of gravel required with 12 cm i.e. 0.12m width = volume of remaining area = area * depth = 84*0.12 = 10.08 m....simple - 9 years agoHelpfull: Yes(9) No(0)
- length becomes 17+3=20 so the quantity required is 2(20*1.5*12/100) + 2(8*1.5*12/100) = 10.08
- 10 years agoHelpfull: Yes(4) No(2)
- All solutions mentioned here are wrong. The right answer is 9.84. (which is not there in the options)
Here is the reasoning :
When you lay a 1.5 m wide path around a rectangle, the corners have to be curved. This is because, if you form another rectangle outside this rectangle, the distance between two corresponding corners will become more than 1.5m.
Hence, at the 4 corners, we will get 4 quarter cylinders. Therefore, the volume of gravel at corners = 4 x (vol. of 1 quarter cylinder)
= 4 x (1/4*(pi)*r*r*h )
= (pi)*r*r*h
where r = 1.5 m and h = 0.12 m
Then, we will add the volume of remaining 4 cuboid (formed between the sides of inner rectangle and outer one ).
Area of 4 cuboid = [2 x (17*0.12*1.5)] + [2 x (8*0.12*1.5)]
Thus, adding all the volumes, we will get = 9.84 as the answer - 10 years agoHelpfull: Yes(3) No(21)
- plzzz xplain clearly
- 10 years agoHelpfull: Yes(2) No(0)
- @Amitabh, why did you multiply 84 with 0.12
- 9 years agoHelpfull: Yes(2) No(0)
- volume of larger cuboid(l=20,b=11,h=0.12) vol1= 26.4
Volume of smaller cuboid(l=17,b=8,h=0.12) vol2=16.32
Therefore volume of path=vol1-vol2=26.4-16.32
=10.08 . - 6 years agoHelpfull: Yes(2) No(0)
- can u explain it clearly
- 10 years agoHelpfull: Yes(1) No(1)
- plz explain
- 10 years agoHelpfull: Yes(0) No(1)
- Answer is (d).
- 10 years agoHelpfull: Yes(0) No(2)
- (d) Total volume=2(1.5*17*0.12)+2(1.5*8*0.12)+4(1.5*1.5*0.12)=10.08 m^2
- 9 years agoHelpfull: Yes(0) No(0)
- Guys he multiplied 12/100 because its the depth otherwise the answer would be in terms of area
- 4 years agoHelpfull: Yes(0) No(0)
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