How many 5’s will be there in the number 121,122,123,... till 356
a. 51
b. 54
c. 50
d. 49

• 121 to 200 => 125,135,145, from 150 to 159 => 11 5's , 165,175,185,195 total=18
  
  201 to 300 => 205,215,225,235,245, 250 to 259 => 11 5's , 265,275,285,295 total=20
  
  301 to 356 => 305,315,325,335,345,350,351,352,353,354,355(2 5's),356 => total=13
  
  total 5's = 18+20+13 = 51
• 10 years agoHelpfull: Yes(42) No(4)
• Upto 149, there will be one 5 in each set of 10 numbers viz.
  121-130= no of 5's=1
  131-140= no of 5's=1
  141-150= no of 5's=2
  151-160=no of 5's=10
  161-170= no of 5's=1
  171-180= no of 5's=1
  181-190= no of 5's=1
  191-200= no of 5's=1
  Similarly it can be found that there will be (8+10=)18 5's in 201 to 300.
  From 301 to 349 there will be 5 occurences of 5's and from 350-356 there will be 8 occurences of the digit 5.
  
  SO in total, no of occurences of digit 5 in the number range of 121 to 356= 18+18+13= 49.
• 10 years agoHelpfull: Yes(5) No(6)
• from 121 to 200 =>18
  From 201 to 300 =>20
  From 301 to 356=> 13
  18+20+13=51
• 9 years agoHelpfull: Yes(3) No(1)
• ans is 51
  
• 9 years agoHelpfull: Yes(0) No(3)
• 51
  bcoz of
  18+20+13
• 8 years agoHelpfull: Yes(0) No(3)
• are kaise aa raha hai bhai ?"
• 6 years agoHelpfull: Yes(0) No(0)